Answer:
The area of triangle K is 16 times greater than the area of triangle J
Step-by-step explanation:
we know that
If Triangle K is a scaled version of Triangle J
then
Triangle K and Triangle J are similar
If two triangles are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
Ak ------> the area of triangle K
Aj -----> the area of triangle J
so
we have
substitute
therefore
The area of triangle K is 16 times greater than the area of triangle J
Answer:
250 ft
Step-by-step explanation:
circumference of circle 'C' is defined as
C = 2πr
250π = 2πr
r = 250π/2π
r= 125
d = 2r = 2×125 = 250
.
diameter of the given circle is 250 ft
Usually, quadratic equations equal 0, and to find the solution you need to make x equal the value that, when added or subtracted to the rest of its bracket, makes 0. This means that your answer is (x + 5)(x - 2) = 0, because 5 - 5 = 0 and 2 - 2 = 0. I hope this helps! Let me know if you would like me to explain further :)
Answer:
25π units^2
Step-by-step explanation:
The shape is a quarter circle with radius 10 units.
area of circle = πr^2
area of a quarter circle = (1/4)π(10 units)^2
area = 25π units^2
Answer:
D. 5x^2 + 2y^2 + 12x + 5y
Step-by-step explanation:
6x + 2y + y^2 + 6x + 2y + y^2 + 4x^2 + x^2 + y
6x + 6x = 12x
12x + 2y + y^2 + 2y + y^2 + 4x^2 + x^2 + y
2y + 2y + y = 5y
12x + 5y + y^2 + y^2 + 4x^2 + x^2
y^2 + y^2 = 2y^2
2y^2 + 4x^2 + x^2 + 12x + 5y
4x^2 + x^2 = 5x^2
2y^2 + 5x^2 + 12x + 5y
5x^2 + 2y^2 + 12x + 5y
