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Svetllana [295]
3 years ago
14

Subtract. 17 – (–11) A. –28 B. –6 C. 6 D. 28

Mathematics
2 answers:
Elis [28]3 years ago
4 0
The answer is 28



Hope this helped
olga nikolaevna [1]3 years ago
4 0
Tricky, Tricky

17-(-11)

There's an imaginary 1 in front of the parentheses...

17-1(-11)

Now multiply

-1*-11=11

17+11=28

Thus,your answer is, D.
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What is the measure of the complement of JKI? the supplement
Anna71 [15]

The answer would be 35 and for supplement it would be 125

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3 years ago
The measures of two exterior angles of a decagon are 97° and 89°. What is the sum of the remaining exterior angles?
gayaneshka [121]

Answer:

the sum of the remaining exterior angles is 174⁰

Step-by-step explanation:

Given;

the measure of two exterior angles of a decagon = 97° and 89°

The total sum of exterior angles of a polygon is 360⁰

let the sum of the remaining exterior angles = x

sum of the given exterior angles = 97⁰ + 89⁰ = 186⁰

x + 186⁰ = 360⁰

x = 360⁰ - 186⁰

x = 174⁰

Therefore, the sum of the remaining exterior angles is 174⁰

6 0
3 years ago
Which of the following
Archy [21]

The answer you are looking for is 36.

If you line up the numbers numerically (4, 8, 16, 32, 36, 64), you'll see that there's a pattern. Each number, multiplied by 2, gets the next number in the sequence. 4 * 2 = 8, 8 * 2 = 16, 16 * 2 = 32, and 32 * 2 = 64.

Thus meaning 36 is the odd number out. I hope this helps!

6 0
4 years ago
Read 2 more answers
The force of gravity on Mars is different than on Earth. The function of the same situation on Mars would be represented by the
sweet-ann [11.9K]

Answer:

If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.

Step-by-step explanation:

Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

v=v_0+a\,*\,t\\y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.

Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

v=v_0+a\,*\,t\\0=v_0-g\,*\,t\\t=\frac{v_0}{t}

When we use this to replace the 't" in the displacement formula, we et:

y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2\\y-y_0=v_0\,(\frac{v_0}{g} )-\frac{g}{2} \,(\frac{v_0}{g} )^2\\y-y_0=\frac{1}{2} \frac{v_0^2}{g}

This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)

And we can also answer the question about time, since given the same initial velocity v_0 , the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)

3 0
3 years ago
I request assistance on answering this question
Ket [755]
The answer is going to be6/8
6 0
3 years ago
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