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Harlamova29_29 [7]
3 years ago
8

Sound travels about 750 miles per hour. If you stand in a canyon and sound a horn, you will hear an echo.

Mathematics
1 answer:
cricket20 [7]3 years ago
8 0

Answer:

The sound takes time to go to a point and reflect back to your position.

It means the sound went twice a distance.

=> Suppose it takes about 0.5 seconds to hear the echo, the canyon wall would be [750 x (0.5/3600)]/2 = 0.052 miles

=> Suppose it takes about n seconds to hear the echo, the canyon wall would be [750 x (n/3600)]/2 miles

Hope this helps!

:)

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Which set of three angles could represent the interior angles of a triangle?
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Answer:

A. 19,70,91

Step-by-step explanation:

Interior angle =180

19+70+91=180

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Can, you please answer this i will give brainliest!
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Answer:

0.6

Step-by-step explanation:

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Suppose that a box contains r red balls and w white balls. Suppose also that balls are drawn from the box one at a time, at rand
dybincka [34]

Answer: Part a) P(a)=\frac{1}{\binom{r+w}{r}}

part b)P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}

Step-by-step explanation:

The probability is calculated as follows:

We have proability of any event E = P(E)=\frac{Favourablecases}{TotalCases}

For part a)

Probability that a red ball is drawn in first attempt = P(E_{1})=\frac{r}{r+w}

Probability that a red ball is drawn in second attempt=P(E_{2})=\frac{r-1}{r+w-1}

Probability that a red ball is drawn in third attempt = P(E_{3})=\frac{r-2}{r+w-1}

Generalising this result

Probability that a red ball is drawn in [tex}i^{th}[/tex] attempt = P(E_{i})=\frac{r-i}{r+w-i}

Thus the probability that events E_{1},E_{2}....E_{i} occur in succession is

P(E)=P(E_{1})\times P(E_{2})\times P(E_{3})\times ...

Thus P(E)=\frac{r}{r+w}\times \frac{r-1}{r+w-1}\times \frac{r-2}{r+w-2}\times ...\times \frac{1}{w}\\\\P(E)=\frac{r!}{(r+w)!}\times (w-1)!

Thus our probability becomes

P(E)=\frac{1}{\binom{r+w}{r}}

Part b)

The event " r red balls are drawn before 2 whites are drawn" can happen in 2 ways

1) 'r' red balls are drawn before 2 white balls are drawn with probability same as calculated for part a.

2) exactly 1 white ball is drawn in between 'r' draws then a red ball again at (r+1)^{th} draw

We have to calculate probability of part 2 as we have already calculated probability of part 1.

For part 2 we have to figure out how many ways are there to draw a white ball among (r) red balls which is obtained by permutations of 1 white ball among (r) red balls which equals \binom{r}{r-1}

Thus the probability becomes P(E_i)=\frac{\binom{r}{r-1}}{\binom{r+w}{r}}=\frac{r}{\binom{r+w}{r}}

Thus required probability of case b becomes P(E)+ P(E_{i})

= P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}\\\\

7 0
3 years ago
Whats the are partial products of 35 x 7?<br><br> (ITS NOT 245)
never [62]
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skad [1K]

Answer:

The height is 0 when it "drops".

3/2x + 9 = 0

3/2x = -9

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3 = -18x

3/-18x

Change signs, time cant be negative.

x= 6

Another interpretation; Slope is negative it is falling. This interpretation is more accurate.

-3/2x + 9 = 0

-3/2x = -9

-3 = -9(2x)

-3 = -18x

6 = x

AFTER 6 SECONDS

7 0
3 years ago
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