Answer:
=3x+27y−6
Step-by-step explanation:
3(3x−(2−6y+2x)+3y)
=(3)(3x+−2+6y+−2x+3y)
=(3)(3x)+(3)(−2)+(3)(6y)+(3)(−2x)+(3)(3y)
=9x−6+18y−6x+9y
=3x+27y−6
Here is the answer I hope it helps
1. 7 and -7 are both 7 units away from 0. They are 14 units away from each other. Absolute value helps because rather than 7+(-7) being 0 absolute value makes anything positive so it becomes 7+7=14 to be able to count the units between the two.
2. 5 and -5 are both 5 units away from 0. They are 10 units away from each other. Absolute value helps because rather than 5+(-5) being 0 absolute value makes anything positive so it becomes 5+5=10 to be able to count the units between the two.
3. 2 and -2 are both 2 units away from 0. They are 4 units away from each other. Absolute value helps because rather than 2+(-2) being 0 absolute value makes anything positive so it becomes 2+2=4 to be able to count the units between the two.
Hope that helps
Answer:
it is 8 if i substitute x for 3
Step-by-step explanation: