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11111nata11111 [884]
3 years ago
9

Can someone help me out with this problem How tall is a stack of cube shaped blocks whose volumes are 375 cube inches, 648 cube

inches, and 1029 cube inches?
Mathematics
1 answer:
S_A_V [24]3 years ago
7 0

Answer:

<em>The stack of blocks is 25.96 inches tall</em>

Step-by-step explanation:

<u>The Volume of a Cube</u>

Given a cube-shaped figure of side length L, the volume is calculated by:

V=L^3

If the volume is known, then the side length can be found by solving for L:

L=\sqrt[3]{L}

We are given three cube-shaped blocks with known volumes. We'll find the individual side lengths and add them up to find the height that results when they stack up vertically.

Block 1, volume 375 cube inches:

L_1=\sqrt[3]{375}=7.21\ inch

Block 2, volume 648 cube inches:

L_2=\sqrt[3]{648}=8.65\ inch

Block 3, volume 1029 cube inches:

L_3=\sqrt[3]{1029}=10.10\ inch

Total height=7.21 inch+8.65 inch+10.10 inch=25.96 inch

The stack of blocks is 25.96 inches tall

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According to records, the amount of precipitation in a certain city on a November day has a mean of 0.10 inches, with a standard
Andru [333]

Answer:

The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days

P(X≤ 0.11) = 0.4404

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean of the Population = 0.10 inches

Given that the standard deviation of the population = 0.07inches

Let 'X' be a random variable in a normal distribution

Z = \frac{x-mean}{S.D} = \frac{0.11-0.10}{0.07} = 0.1428

<u><em>Step(ii):-</em></u>

The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days

P(X≤ 0.11) = P(Z≤0.1428)

               =  1-P(Z≥0.1428)

              =  1 - ( 0.5 +A(0.1428)

            =  0.5 - A(0.1428)

            = 0.5 -0.0596

           = 0.4404

<u><em>Final answer:-</em></u>

The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days

P(X≤ 0.11) = 0.4404

8 0
2 years ago
Keisha needs to make at least 32 costumes for the school play. Since she can make 4 costumes each week, Keisha plans to work on
Licemer1 [7]

Complete question is;

Keisha needs to make at least 32 costumes for the school play. Since she can make 4 costumes each week, Keisha plans to work on the costumes for at least 8 weeks.

Which inequality matches the problem?

A) x ≥ 8

B) x = 8

C) x ≤ 8

D) none of the above

Answer:

A: x ≥ 8

Step-by-step explanation:

Let the number of weeks be x.

She needs to make at least 32 costumes and plans to work at least 8 weeks. Since she makes 4 costumes per week, we can say that;

4x ≥ 32

I used greater than or equal to sign because she can't make less than 32 costumes.

Also, she can't use less than 8 weeks.

Thus; dividing both sides by 4, we have;

4x/4 ≥ 32/4

x ≥ 8

4 0
3 years ago
Mr. Nelson wants to put chicken wire around his chicken coup. He purchased 28.2 feet of chicken wire. The cost was $0.55 per foo
Shalnov [3]

Answer: $15.51

Step-by-step explanation: 28.2 times 0.55 is $15.51

6 0
3 years ago
Read 2 more answers
Are the lines (-6,-2) and (2,3) perpendicular ?
morpeh [17]

Answer:

Step-by-step explanation:

No

4 0
2 years ago
Read 2 more answers
Please answer !!!!!!!
Akimi4 [234]

The measure of all the angles is given below:

angle 1= 30

angle 2=  150

angle 3= 30

angle 4= 150

angle 5= 30

angle 6= 150

angle 7= 30

angle 8= 73.5

<h3>What is angle?</h3>

An angle is formed when two straight lines or rays meet at a common endpoint. The common point of contact is called the vertex of an angle.

As,

angle 1= 30 (Vertically opposite angle)

angle 7= 30 (corresponding angle)

angle 4+30= 180 (linear pair)

 angle 4= 150

angle 4= angle 2= 150 (Vertically opposite angle)

angle 2= angle 6= 150  (corresponding angle)

angle 1= angle 5= 30  (corresponding angle)

angle (2x+3)= angle 4  (corresponding angle)

     2x+3= 150

      x= 73.5

Lean more about angle here:

brainly.com/question/13954458

#SPJ1      

7 0
1 year ago
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