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Mamont248 [21]
3 years ago
8

nelson got a pack of 12 pencils he took 3 pencils to pit in his desk at school and 2 pencils to put in his locker at school. wha

t is the fraction of total pencils that nelson took to school
Mathematics
2 answers:
g100num [7]3 years ago
6 0
 the fraction of pencils he took to school is 
5/12
sattari [20]3 years ago
4 0
Nelson took a total of 5 pencils to school and he bought 12 so the fraction would be 5 over 12
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Kol and Kara solve this problem in two different ways the perimeter of a rectangle is 46 centimeters it’s length is 8 centimeter
JulsSmile [24]

Answer:

15cm

Step-by-step explanation:

because length is given as 8 cm and perimeter is length+width+length+width

so if you take 8cmX2 since its taken twice to get the perimeter and 15cmX2 you get 46cm which originally the question said was the peemiter

5 0
2 years ago
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2 (x+8)
antoniya [11.8K]

Answer:

Step-by-step explanation: its 1.87

5 0
3 years ago
Linear and nonlinear functions​
Delicious77 [7]

Answer:

Step-by-step explanation:

6 0
3 years ago
Use the quadratic regression to find the equation for the parabola going through these 3 points (-5, 161) (-2, 29) (6, 205)
Rama09 [41]

Answer:

The equation of the parabola is y = 6x^{2}-2b+1

Step-by-step explanation:

First we write a quadratic equation of parabola as y = ax^{2}+bx+c

Now it is given in the question that parabola passes through three points (-5,161),(-2,29),(6,205).

To find the equation we have to get the value of a,b & c.

Now we form three equations to find the value of a,b,c.

We put the value (-5,161) in the equation

161 = a×25+b×(-5)+c

161 = 25a-5b+c----------(1)

Now we put (-2,29) in the equation

29 = a×4+b×(-2)+c

29 = 4a-2b+c---------(2)

Again we put (6,205) in the equation

205 = a×36+6b+c------------(3)

Now we subtract equation (1) from (2)

161-29 = 25a-4a-5b-(-2b)+c-c

132 = 21a-5b+2b

132 = 21a-3b

132 = 3(7a-b)

44 = 7a-b---------(4)

Now we subtract equation (2) from (3)

205-29 = 36a-4a+6b-(-2b)+c-c

176 = 32a+6b+2b

176 = 32a+8b

176 = 8(4a+b)

22 = 4a+b------------(5)

Now we add equation (5) and (4)

44+22 = 7a+4a-b+b

66 = 11a

a = 6

Now we put the value a in equation (4)

44 = 7×6-b

44 = 42-b

44-42 = -b

2 = (-b)

b = (-2)

Now we put the value of a and b in equation number (2)

29 = 4×6-2(-2)+c

29 = 24+4+c

29 = 28+c

c = 29-28

c =1

Finally we put the value of a,b,c in the quadratic equation

y = 6x^{2}+(-2)x+1

y = 6x^{2}-2+1

This is the final answer.

6 0
3 years ago
Fifth grade
Harman [31]

Answer:

Length = 5 cm, width = 2 cm.

Step-by-step explanation:

If L is the length and W the width we have the equations:

LW = 10            <-----  The area.

2L + 2W = 14      <------ The perimeter.

From the first equation L = 10/W so substituting for L in the second equation:

2 * 10/W + 2W = 14

20/W + 2W = 14             Multiplying through by W:

20 + 2W^2 = 14W

2W^2 - 14W + 20 = 0      Dividing by 2:

W^2 - 7W + 10 = 0  

(W - 5)(W - 2) = 0

W = 5 or 2.

So W is either  2 or 5 cm.

Substituting W = 2 in LW = 10

L * 2 = 10

L = 5 cm.

The length is longer than the width so the length is 5 cm and the width = 2 cm.

7 0
3 years ago
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