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NeTakaya
3 years ago
15

Indicate which of the following situations inferential statistics: a. An annual stockholders' report details the assets of the c

orporation. b. A history instructor tells his class the number of students who received an A on a recent exam. c. The mean of a sample set of scores is calculated to characterize the sample. d. The sample data from a poll are used to estimate the opinion of the population. e. A correlational study is conducted on a sample to determine whether educational level and income in the population are related. f. A newspaper article reports the average salaries of federal employees from data collected on all federal employees.
Mathematics
1 answer:
Aliun [14]3 years ago
6 0

Answer:

The situations c, d and e are Inferential statistics.

Step-by-step explanation:

Inferential statistics is used to determine reasons for a situation or phenomenon. It helps to draw conclusions grounded on extrapolations, and is hence fundamentally dissimilar from descriptive statistics that only summarizes the data that has truly been measured.

Descriptive statistics are short-term descriptive coefficients that condenses a given data set, which can be a demonstration of the whole or a sample of a whole population.

All descriptive statistics are either central tendency measure or variability measure. Measures of central tendency define the epicenter position of a distribution for a data set.  

From the provided situations the Inferential statistics are:

c. The mean of a sample set of scores is calculated to characterize the sample.

d. The sample data from a poll are used to estimate the opinion of the population.

e. A correlational study is conducted on a sample to determine whether educational level and income in the population are related.

Thus, the situations c, d and e are Inferential statistics.

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Is perpendicular to and passes through point C(5, 12).
uysha [10]

If CD is perpendicular on AB then the x intercept of CD is (17,0).

Given that CD is perpendicular on AB and passes through C(5,12) and the coordinates of A and B are  (-10,-3), (7,14).

When two lines are perpendicular on other line then the product of their slopes is equal to -1.

It is given that CD is perpendicular on AB. So we need to first calculate the slope of AB.

Slope=(y_{2} -y_{1} /x_{2} -x_{1} )

Slope of AB=(14+3/7+10)

=(17/17)

=1

According to rule product of slopes of AB and CD should be -1.

So the slope of CD will be -1.

Now we have to form equation of CD from slope -1 and point (5,12).

y-12=-1(x-5)

y-12=-x+5

x+y-17=0

We have to find out x intercept.

We know that x intercept is a point where the line touches x axis. So here the value of y =0.

x+y-17=0

put the value of y=0.

x+0-17=0

x=17

Point will be (17,0)

Hence the x intercept of CD will be (17,0).

Learn more about intercepts at brainly.com/question/24212383

#SPJ1

Question is incomplete as it should include in its beginning that CD is perpendicular on AB.

8 0
2 years ago
PLZ HELP!! brainliest and 40pnts
o-na [289]

Answer:

PT 1: C

PT 2: B

Step-by-step explanation:

In order to find the volume of a cone use equation

V=\pi r^2\frac{h}{3}

To find the volume of a cylinder use equation

V=\pi r^2h

3 0
3 years ago
Your classmate suggests that the margin of error in the interval could be reduced if the confidence level were changed to 90% in
lys-0071 [83]

Answer:

Yes

Step-by-step explanation:

Given that your classmate suggests that the margin of error in the interval could be reduced if the confidence level were changed to 90% instead of 95%.

This is a true statement

Reason:

Confidence interval = mean±margin of error

margin of error = Critical value * Std error

Thus we have the higher the margin of error the wider the confidence interval.

And the higher the critical value the higher the margin of error.

In other words  when confidence level is reduced from 95% to 90% we get reduced critical value and as a result narrower confidence interval.

True statement

4 0
4 years ago
3a+2x-3y=15<br>Solve for a.<br>Then Solve put the value for a =<br>a+7÷10​
erma4kov [3.2K]

\huge\bf Question:–

\sf \longmapsto \: 3a+2x−3y=15

\bf \huge \: To  \: Find:–

\boxed{\bf \: Value\: of  \: A}

\huge\bf Solution:–

\sf \longmapsto \: 3a+2x−3y=15

\boxed{ \bf \: Add -2x  \: to  \: both  \: sides}

\sf \longmapsto \: 3a+2x−3y+−2x=15+−2x

\sf \longmapsto \: 3a−3y=−2x+15

\boxed{ \bf \: Add  \: 3y  \: to \:  both  \: sides}

\sf \longmapsto \: 3a−3y+3y=−2x+15+3y

\sf \longmapsto \: 3a=−2x+3y+15

\boxed{\bf \:  \: Divide  \: both  \: sides \:  by \:  3}

\sf \longmapsto \:  \dfrac{3a}{3} =  \dfrac{−2x+3y+15}{3}

\boxed{\bf \:  Cross \: Multiply}

\boxed{\sf \longmapsto \: a =  \dfrac{ - 2}{3} x + y + 5}

______________________________________

\bf \: Put\:The\: Value

\sf \longmapsto \: \dfrac{−2x+3y+15}{3}  +7÷10

\boxed{\bf \: Distribute}

\sf \longmapsto \: \dfrac{ - 2}{3} x+y+5+ \dfrac{7}{10}

\boxed{\bf \: Combine \:  Like \:  terms}

\sf \longmapsto \: \bigg( \dfrac{ - 2}{3} x\bigg) + y +\bigg( 5 +  \dfrac{7}{10} \bigg)

\sf \longmapsto \:  \dfrac{ - 2}{3} x + y +  \dfrac{57}{10}

______________________________________

\boxed{\bf The Answer\: is:–}

\boxed{{\underline{\bf\dfrac{ - 2}{3} x + y +  \dfrac{57}{10}} }}

8 0
2 years ago
Read 2 more answers
Which expression is equivalent to -5a + 12b - c + 5a - 7b + 12c after combining like terms?
just olya [345]

Answer:

5b + 12c

Step-by-step explanation:

-5a +5 a = 0

12b-7b = 5b

12c= 12c

therefore you have the expression 5b+12c

4 0
3 years ago
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