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3 years ago

If i'm a size 9 in womens what size am i in men's

Mathematics

2 answers:

Shkiper50 [21]3 years ago

6 0

Im an 7 1/2 in womens and an 21 or 22 in mens so your between 23 and 26 hope that helps

Leya [2.2K]3 years ago

4 0

I am a size 12 in women and I wear a size 26 in men but I still have a little room. You should try a size 22 maybe?

You might be interested in

Jason ran 325 meters farther than Kim ran. Kim ran 4.2 kilometers. how many meters did Jason run?

notka56 [123]

4200= 4.2 km so
4200 + 325= 4525 meters
jason ran 4525 meters

6 0

2 years ago

Will give BRAINLIEST

likoan [24]

Answer:

Quadrant 1 (1,5)

Step-by-step explanation:

3 0

1 year ago

Read 2 more answers

15. If x=a Sin2t (I+Cos2t) and y=b Cos 2t (1-Cos2t) then find dy/dx at =22/7*4

Sav [38]

By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}$

It looks like we're given

$\begin{cases}x=a\sin(2t)(1+\cos(2t))\\y=b\cos(2t)(1-\cos(2t))\end{cases}$

where a and b are presumably constant.

Recall that

$\cos^2t=\dfrac{1+\cos(2t)}2$

$\sin^2t=\dfrac{1-\cos(2t)}2$

so that

$\begin{cases}x=2a\sin(2t)\cos^2t\\y=2b\cos(2t)\sin^2t\end{cases}$

Then we have

$\dfrac{\mathrm dx}{\mathrm dt}=4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t$

$\dfrac{\mathrm dy}{\mathrm dt}=-4b\sin(2t)\sin^2t+4b\cos(2t)\sin t\cos t$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4b\cos(2t)\sin t\cos t-4b\sin(2t)\sin^2}{4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t}$

$\implies\boxed{\dfrac{\mathrm dy}{\mathrm dx}=\dfrac ba\tan t}$

where the last reduction follows from dividing through everything by $\cos(2t)\cos^2t$ and simplifying.

I'm not sure at which point you're supposed to evaluate the derivative (22/7*4, as in 88/7? or something else?), so I'll leave that to you.

8 0

2 years ago

I need help with Math ASAP plz!!

True [87]

Answer:

x = (74-28)/2

Step-by-step explanation:

We find the perimeter of a triangle by adding the sides together

s1 +s2+s3 = P

The perimeter is 74

s1 +s2+s3 = 74

We know one of the sides is 28

28 +s2+s3 = 74

The other two sides are equal in length, call them x

28 +x+x = 74

Combine like terms

28+2x = 74

We want to solve for x

Subtract 28 from each side

28-28+2x = 74-28

2x = 74-28

Divide each side by 2

2x/2 = (74-28)/2

x = (74-28)/2

4 0

2 years ago

Asap please help! and explain how you got the answer!

Inessa [10]

55

To start to solve this problem we start by observing what information there is. We need y, to find y we have to know x. We need x to find y because all the angles in a triangle add up to 180. If we find x we can subtract the angles we know and get y. To find x we look and see that it is on a straight line, and on the other side of the line is 100. We know that a straight line is 180 degrees so we subtract 100 from 180 to get x. We now know x is 80, so now we minus 89 and 45 from 180. We get 55. This means that y is 55.

Hope this helps! Please make me the brainliest, it’s not necessary but appreciated, I put a lot of effort and research into my answers. Have a good day, stay safe and stay healthy.

7 0

2 years ago