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pychu [463]
3 years ago
14

Which numbers are a distance of 3 units from 12 on a number line?

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
3 0
15 I think i'm sorry if i'm wrong 
Likurg_2 [28]3 years ago
3 0

Answer:

Probably 15 and 9

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Please solve this question. It's about inverse matrix. ASAP!!​
sweet-ann [11.9K]

Answer:

Step-by-step explanation:

A=\begin{bmatrix}2&3\\4&7\end{bmatrix}\\\\A^{-1} =\begin{bmatrix} \dfrac{7}{2} & \dfrac{-3} {2}\\-2&1 \end{bmatrix}\\\\A*A^{-1}=1\pi_2=T\\\\A^2+3T=\begin{bmatrix} 14&27\\36&61 \end{bmatrix}+\begin{bmatrix} 1&0\\0&1 \end{bmatrix}=\begin{bmatrix} 17&27\\36&64 \end{bmatrix}

4 0
2 years ago
Help!<br><br> I fallen and can’t get up.
Gnom [1K]
I miss when everyone always said this

good times but ty for the points
7 0
3 years ago
Read 2 more answers
Please help and thank you
tatiyna

Answer:

b_{1}=\frac{2A}{h}-b_{2}

Step-by-step explanation:

Given: A=\frac{1}{2}(b_{1} +b_{2})h

We need to completely isolate b_{1} to solve.

A=\frac{1}{2}(b_{1} +b_{2})h

A=(\frac{1}{2}b_{1} +\frac{1}{2} b_{2})h

A=\frac{1}{2}b_{1} h+\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}h+A=\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}h=-A+\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}=\frac{-A}{h}+\frac{1}{2}b_{2}

Finally, multiply both sides by -2 to completely isolate b_{1}.

b_{1}=\frac{2A}{h}-b_{2}

5 0
3 years ago
Read 2 more answers
Pls help I don't understand:
sineoko [7]

Answer:

Part a) T(d)=2d+30

Part b) T(6)=42\ minutes

Step-by-step explanation:

Part a) Write an equation for T (d)

Let

d ----> the number of days

T ---> the time in minutes of the treadmill

we know that

The linear equation in slope intercept form is equal to

T=md+b

where

m is the slope or unit rate

b is the y-intercept or initial value

In this problem we have

The slope or unit  rate is

m=2\ \frac{minutes}{day}

The y-intercept or initial value is

b=30\ minutes

substitute

T(d)=2d+30

Part b) Find T (6), the minutes he will spend on the treadmill on day 6

For d=6

substitute in the equation and solve for T

T(6)=2(6)+30

T(6)=42\ minutes

8 0
3 years ago
What point on the graph of y = 0.5f(x) corresponds to (4, 16)? Explain.
SVETLANKA909090 [29]

We are given a coordinate (4,16).

Where first coordinate is the value of x and second coordinate is the value of y for the function y=f(x).

We need to find the value of given point (4,16) for function y= 0.5f(x).

Here function f(x) is being multiplied by 0.5.

On multiplying 0.5 by y, it will effect the value of y only. It does not effect value of  x . Because x value is still x. Only function f(x) is being multiplied by 0.5.

Therefore, y= 0.5f(4) = 0.5 * 16 = 8.

So, (4,8) is the point on the graph of y = 0.5f(x) corresponds to (4, 16).

4 0
3 years ago
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