All categories

3 years ago

Which numbers are a distance of 3 units from 12 on a number line?

Mathematics

2 answers:

goldfiish [28.3K]3 years ago

3 0

15 I think i'm sorry if i'm wrong

Likurg_2 [28]3 years ago

3 0

Answer:

Probably 15 and 9

You might be interested in

Please solve this question. It's about inverse matrix. ASAP!!

sweet-ann [11.9K]

Answer:

Step-by-step explanation:

$A=\begin{bmatrix}2&3\\4&7\end{bmatrix}\\\\A^{-1} =\begin{bmatrix} \dfrac{7}{2} & \dfrac{-3} {2}\\-2&1 \end{bmatrix}\\\\A*A^{-1}=1\pi_2=T\\\\A^2+3T=\begin{bmatrix} 14&27\\36&61 \end{bmatrix}+\begin{bmatrix} 1&0\\0&1 \end{bmatrix}=\begin{bmatrix} 17&27\\36&64 \end{bmatrix}$

4 0

2 years ago

Help!<br><br> I fallen and can’t get up.

Gnom [1K]

I miss when everyone always said this

good times but ty for the points

7 0

3 years ago

Read 2 more answers

Please help and thank you

tatiyna

Answer:

$b_{1}=\frac{2A}{h}-b_{2}$

Step-by-step explanation:

Given: $A=\frac{1}{2}(b_{1} +b_{2})h$

We need to completely isolate $b_{1}$ to solve.

$A=\frac{1}{2}(b_{1} +b_{2})h$

$A=(\frac{1}{2}b_{1} +\frac{1}{2} b_{2})h$

$A=\frac{1}{2}b_{1} h+\frac{1}{2}b_{2}h$

$-\frac{1}{2}b_{1}h+A=\frac{1}{2}b_{2}h$

$-\frac{1}{2}b_{1}h=-A+\frac{1}{2}b_{2}h$

$-\frac{1}{2}b_{1}=\frac{-A}{h}+\frac{1}{2}b_{2}$

Finally, multiply both sides by -2 to completely isolate $b_{1}$ .

$b_{1}=\frac{2A}{h}-b_{2}$

5 0

3 years ago

Read 2 more answers

Pls help I don't understand:

sineoko [7]

Answer:

Part a) $T(d)=2d+30$

Part b) $T(6)=42\ minutes$

Step-by-step explanation:

Part a) Write an equation for T (d)

Let

d ----> the number of days

T ---> the time in minutes of the treadmill

we know that

The linear equation in slope intercept form is equal to

$T=md+b$

where

m is the slope or unit rate

b is the y-intercept or initial value

In this problem we have

The slope or unit rate is

$m=2\ \frac{minutes}{day}$

The y-intercept or initial value is

$b=30\ minutes$

substitute

$T(d)=2d+30$

Part b) Find T (6), the minutes he will spend on the treadmill on day 6

For d=6

substitute in the equation and solve for T

$T(6)=2(6)+30$

$T(6)=42\ minutes$

8 0

3 years ago

What point on the graph of y = 0.5f(x) corresponds to (4, 16)? Explain.

SVETLANKA909090 [29]

We are given a coordinate (4,16).

Where first coordinate is the value of x and second coordinate is the value of y for the function y=f(x).

We need to find the value of given point (4,16) for function y= 0.5f(x).

Here function f(x) is being multiplied by 0.5.

On multiplying 0.5 by y, it will effect the value of y only. It does not effect value of x . Because x value is still x. Only function f(x) is being multiplied by 0.5.

Therefore, y= 0.5f(4) = 0.5 * 16 = 8.

So, (4,8) is the point on the graph of y = 0.5f(x) corresponds to (4, 16).

4 0

3 years ago