Graph the line passing through the given point and having the given slope. Give the slope intercept form of the equation of the
2 answers:
You might be interested in
Equation of a tangent line of a curve is:
y- y0 = f´ (x0) (x - x0 ). In this case: x0=1, y0=1
f´(x)=
(Derivation)
f´(x0)=
y - 1 = 1/2 ( x - 1 )
y - 1 = 1/2 x - 1/2
y = 1/2 x - 1/2 + 1
y =
y- y0 = f´ (x0) (x - x0 ). In this case: x0=1, y0=1
f´(x)=
f´(x0)=
y - 1 = 1/2 ( x - 1 )
y - 1 = 1/2 x - 1/2
y = 1/2 x - 1/2 + 1
y =