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aleksley [76]
3 years ago
11

Graph the line passing through the given point and having the given slope. Give the slope intercept form of the equation of the

line if possible. (1,-2) m=-1/2
Mathematics
2 answers:
makkiz [27]3 years ago
8 0
Y - y₁ = m(x - x₁)
y - (-2) = -¹/₂(x - 1)
y + 2 = -¹/₂(x - 1)
y + 2 = -¹/₂x + ¹/₂
<u>    - 2            - 2   </u>
       y = -¹/₂x - 1¹/₂
shutvik [7]3 years ago
6 0
Equation of the line is y=mx+b
the line passing through point (1;-2) so x=1 y=-2
m=-0.5 so put all these values in equetion and found value of b
-2=-0.5*1+b
-2=-0.5+b
b=-1.5
so equation of the line is y=-0.5x-1.5
Answer:
equation of the line is y=-0.5x-1.5



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Answer:

W(t)=5.5t+79.5.

Step-by-step explanation:

Please consider the complete question.

A young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly. He gained weight at a rate of 5.5 kilograms per month. After 11 months, he weighed 140 kilograms. Let W(t) denote the sumo wrestler's weight W(measured in kilograms) as a function of time t (measured in months).  

Since wrestler gained weight at a rate of 5.5 kilograms per month, so slope of line be 5.5.

Now, we will use point-slope form of equation as:

y-y_1=m(x-x_1), where,

m = Slope

(x_1,y_1) = Given point on the line.

Upon substituting coordinates of point (11,140) in above formula, we will get:

y-140=5.5(x-11)

y-140=5.5x-60.5

y-140+140=5.5x-60.5+140

y=5.5x+79.5

Therefore, our required function would be W(t)=5.5t+79.5.

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