Step-by-step explanation:
<h3>
<em><u>Josh and pa are the ones who is not compl and the rust of you is a good idea but you are a great Mama and a good one se and I have eye contact and have to write a book nnk</u></em></h3>
Answer:
See explanation below
Step-by-step explanation:
<u>First we will solve the radical equation</u> (which I guess was problem 1),
Let's start by simplifying it:

Now we will solve the equation by squaring both sides of the equation:

So the calculation for x was that x = -10
However, this does not produce a solution to the equation: When we plug this value into the radical equation we get:

This happens because <u>when we first squared both sides of the equation in the first part of the problem we missed one value for x </u>(remember that all roots have 2 answers, a positive one and a negative one) while squares are always positive.
When we squared the root, we missed one value for x and that is why the calculation does not produce a solution to the equation.
Answer:
I have put an image i made. answer - 6.05204
Step-by-step explanation:
pls mark me brainliest :))
8 .5 2 4
× .7 1
+ 8 5 2 4
+ 5 9 6 6 8
______________________________
= 6 .0 5 2 0 4

Given :


let's solve for f(x) × g(x) :



therefore, correct choice is : D
7.5x18.74= 140.55 is the correct answer