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Vitek1552 [10]
3 years ago
12

What is the Golden Rule of Solubility? A. polar dissolves nonpolar. B. nonpolar dissolves polar. C. like dissolves unlike D. lik

e dissolves like
Chemistry
1 answer:
DerKrebs [107]3 years ago
4 0

Answer: D. like dissolves like

Explanation:

The solubility of substances is governed by: Like dissolves like, which states that polar compounds are soluble in polar solvents and non polar compounds are soluble in non polar solvents.

Hydrocarbons are non polar in nature due to less difference between the electronegativities of carbon and hydrogen and thus are soluble in non polar solvents only.

Ionic compounds which are formed by elements with high electronegativity difference are polar in nature and thus dissolve in polar solvents.

Example: NaCl in water.

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Which roles belong to decomposers? Check all that apply.
Crank

Answer:Decomposers break down waste and dead organisms.

Explanation:

Decomposers help keep the environment clean by acting on waste

8 0
4 years ago
Read 2 more answers
Explain how you would decide which represents a greater mass: 3.25 x 1022 atoms of Ca or 2.45 grams of Mg?
elena55 [62]

Answer:

  • <u>You need to convert the number of atoms of Ca into mass in grams, using Avogadro's number and the atomic mass of Ca.</u>

Explanation:

The amount of matter is measured in grams. Thus, you need to convert the number of atoms of Ca (calcium) into mass to compare with 2.45 grams of Mg.

To convert the atoms of calcium into mass, you divide by Avogadro's number, to obtain the number of moles of atoms, and then divide by the atomic mass of calcium.

<u />

<u>1. Number of moles, n</u>

      n=\dfrac{\text{number of atoms}}{\text{Avogadro's number}}\\ \\ \\ n=\dfrac{3.25\times 10^{22}}{6.022\times 10^{23}}=0.053969mol

<u />

<u>2. Mass</u>

  • mass = number of moles × atomic mass
  • mass = 0.053969mol × 40.078g/mol = 2.16g

Then, 2.45 g of Mg represent a greaer mass than the 3.25 × 10²² atoms of Ca.

4 0
3 years ago
What is the empirical formula for a compound which contains 67.1 zinc and the rest is oxygen
wolverine [178]

Answer:

The empirical formula is ZnO2

Explanation:

What is the empirical formula for a compound which contains 67.1% zinc and the rest is oxygen?

Step 1: Data given

Suppose the compound has a mass of 100.0 grams

A compound contains:

67.1 % Zinc  = 67.1 grams

100 - 67.1 = 32.9 % oxygen  = 32.9 grams

Molar mass of Zinc = 65.38 g/mol

Molar mass of O = 16 g/mol

Step 2: Calculate moles of Zinc

Suppose the compound is 100 grams

Moles Zn = 67. 10 grams / 65.38 g/mol

Moles Zn = 1.026 moles

Step 3: Calculate moles of O

Moles O = 32.90 grams / 16.00 g/mol

Moles O = 2.056 moles

Step 4: Calculate mol ratio

We divide by the smallest amount of moles

Zn: 1.026/1.026 = 1

O: 2.056/1.026 = 2

The empirical formula is ZnO2

To control this we can calculate the % Zinc for 1 mol

65.38 / (65.38+2*16) = 0.67.1 = 67.2 %

7 0
3 years ago
How does the number of valence electrons in an atom relate to the element's
mixer [17]
I believe the answer is A
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3 years ago
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Write the equation for the formation of water gas
GREYUIT [131]

Answer:

the answer is C + H2O # CO + H2.

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3 years ago
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