Answer:
C. ribosomes
Explanation:
Both prokaryotic and eukaryotic cells contain certain structures called ORGANELLES. They possess some in common and others are not found in one or the other. According to this question, a small, free-floating organelle made from nucleic acid and amino acid is found in both eukaryotes and prokaryotes. This organelle is RIBOSOMES.
Ribosomes are organelles responsible for the synthesis of protein in both eukaryotes and prokaryotes. They can be found free-floating or attached to endoplasmic reticulum. Ribosomes are predominantly made of RNA (nucleic acid) and proteins i.e. Ribosomal RNA (rRNA) and proteins is their structural constituent. Hence, the organelle in this question is RIBOSOME.
The quantity of 0.001 m aq naoh needed to neutralize the hcl produced by complete solvolysis is 200 ml.
Solvolysis is a type of nucleophilic substitution or elimination wherein the nucleophile is a solvent molecule. function of SN1 reactions, solvolysis of a chiral reactant provides the racemate.
Calculation :-
using the titration equation,
M₁V₁ = M₂V₂
substituting values
V₁ = M₂ V₂/M₁
= 0.2 × 10 ml /0.01
= 2/0.01 ml
= 200 ml.
A reaction in which the solvent is a reactant, and turns into part of the response product. Hydrolysis of tert-butyl chloride; solvent = water. Fischer esterification reaction; solvent = methanol. related phrases: Alcoholysis, aminolysis.
Learn more about solvolysis here:-brainly.com/question/29555642
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Calculate the quantity of 0.01M aq NaOH needed to neutralize the HCl produced by complete solvolysis of the t-BuCl in 10ml of 0.2M t-BuCl in acetone.
Answer:
0.25L
Explanation:
Using the dilution formula
C1V1=C2V2
C1=6M
V1?
C2=0.75M
V2=2.0L
V1= C2V2/C1
V1=0.75*2.0/6
V1=0.25L
Answer: No reaction occurs
Explanation:.
Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.
The given chemical equation is:

The complete ionic equation is;

The ions which are present on both the sides of the equation are are not involved in net ionic equation.
Hence, there is no net reaction.