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Temka [501]
3 years ago
15

Write the electron configuration​

Chemistry
1 answer:
ycow [4]3 years ago
8 0

Answer:

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5

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A sample of nitric acid has a mass of 8.2g. It is dissolved in 1L of water. A 25mL aliquot of this acid is titrated with NaOH. T
AveGali [126]

Answer:

18.075 mL of NaOH solution was added to achieve neutralization

Explanation:

First, let's formulate the chemical reaction between nitric acid and sodium hydroxide:

NaOH + HNO3 → NaNO3 + H2O

From this balanced equation we know that 1 mole of NaOH reacts with 1 mole of HNO3 to achieve neutralization. Let's calculate how many moles we have in the 25 mL aliquot to be titrated:

63.01 g of HNO3 ----- 1 mole

8.2 g of HNO3 ----- x = (8.2 g × 1 mole)/63.01 g = 0.13014 moles of HNO3

So far we added 8.2 grams of nitric acid (0.13014 moles) in 1 L of water.

1000 mL solution ---- 0.13014 moles of HNO3

25 mL (aliquot) ---- x = (25 mL× 0.13014 moles)/1000 mL = 0.0032535 moles

So, we now know that in the 25 mL aliquot to be titrated we have 0.0032535 moles of HNO3. As we stated before, 1 mole of NaOH will react with 1 mole of HNO3, hence 0.0032535 moles of HNO3 have to react with 0.0032535 moles of NaOH to achieve neutralization. Let's calculate then, in which volume of the given NaOH solution we have 0.0032535 moles:

0.18 moles of NaOH ----- 1000 mL Solution

0.0032535 moles---- x=(0.0032535moles×1000 mL)/0.18 moles = 18.075mL

As we can see, we need 18.075 mL of a 0.18 M NaOH solution to titrate a 25 mL aliquot of the prepared HNO3 solution.

4 0
3 years ago
Petrified fossils are really
Anna35 [415]
I think it would be either dead bodies or rocks? i dont really understand too well but sorry if this doesn’t help!! :((
3 0
2 years ago
You need to determine the mass of an aqueous solution. You determine the mass of your 10.0 mL graduated cylinder to be 23.731 g.
Amanda [17]

Answer: 0.86g/mL

Explanation:

Mass of empty cylinder = 23.731g

Mass of cylinder + liquid = 26.414g

Mass of the liquid = 26.414 — 23.731

= 2.683g

Volume of the liquid = 3.12mL

Density = Mass / volume

Density = 2.683g / 3.12mL

Density = 0.86g/mL

3 0
3 years ago
(a) How many moles of CO2 contain 2.42 ✕ 1024 molecules?
Vikki [24]
Don’t currently have a calculator with me but just use Avogadros constant (A) 6.02x10^24, in the equation n=N/A. Lower case n being the number of mol and upper case being the number of molecules (given).
4 0
2 years ago
What is taxonomic richness
-BARSIC- [3]

Answer:

I think you have a very cool username.

Explanation:

3 0
3 years ago
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