1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VARVARA [1.3K]
3 years ago
7

What is the solution to the equation? 1/4 (3x-16)+1/4x=5 1/3

Mathematics
1 answer:
morpeh [17]3 years ago
6 0
Is that a mixed number 5 and 1/3 at the end? 
If so, we have: 
(1/4)(3x - 16) + (1/4)x = 16/3 
If we multiply everything by 12, the LCD, we can get rid of the fractions. 
This gives us: 
3(3x - 16) + 3x = 4(16) 9x - 48 + 3x = 64 12x = 112 <span>x = 28/3</span>
You might be interested in
Can someone help me ?
Leni [432]

Answer:

d

Step-by-step explanation:

if she connects it to any other point angle would be more the 30 degree

6 0
3 years ago
Read 2 more answers
Please help i don’t know how to find the slope
lilavasa [31]
Y= mx+b is the formula for writing and equation for slope.


M= slope
B= y-intercept

You replace the m and b with the info given to you in the problem.

Answer: y = -3/4x -6
6 0
3 years ago
What is the rate of change between (-32,0) and (-31,2)
Brums [2.3K]
2-0/ -31 - -32
= 2-0/ -31 + 32
= 2/1
= 2
8 0
3 years ago
Which anwser is equal to i^39?​
sleet_krkn [62]

Answer:

Step-by-step explanation:

7 0
4 years ago
What is a three digit number thats an odd multiple of three and the product of its digits is 24 and is larger than 15 squared?
Reika [66]
The only way 3 digits can have product 24 is 
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4 
To be divisible by 3 the sum of the digits must be divisible by 3.
1+  3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3. 

So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.

Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.

The others must end in 3. 

They must be greater than 152 which is 225. So the

First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.

The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.  
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
7 0
3 years ago
Other questions:
  • Number 21 ......................
    15·1 answer
  • What is the Gcf of 6x^3?
    7·1 answer
  • Please help me........​
    14·1 answer
  • Find the number of bricks to be laid in a square path of side 18cm if the side of each square bricks is 3cm
    8·1 answer
  • A square is inscribed in an isosceles right triangle. Length of the leg equals to 2 in. as shown on the figure. Find the perimet
    15·1 answer
  • Ari's teacher says he may have his report grade based on either the mean or the median of his last six test scores
    7·1 answer
  • Chris works in a tall building in downtown
    7·1 answer
  • What is an absolute value
    6·1 answer
  • If H is the circumcenter of triangle BCD, find each measure. CD, CE, HD, GD, HG, HF
    14·1 answer
  • Find the derivative of J(w)= T-Re^x
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!