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3 years ago

Number 18 factor linear expression

Mathematics

1 answer:

notsponge [240]3 years ago

5 0

I don’t have enough information to answer this..... what expression needs to be factored?

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Im having a mental breakdown can someone please just do this for me

topjm [15]

The slopes of the original function y = |x| are m = 1 and m = -1 (m is the variable used to represent slope).

when you add a coefficient (number) in front of |x|, it will either make the slopes steeper or more flat. the larger the value of the coefficient, the steeper the slope will be (vice versa for a coefficient smaller than 1, which would make the slope more flat than the parent(original) function).

because these are absolute value functions, they will have two slopes. one slope for the end going up from left to right, and one for the end going down from left to right. this means that one slope must be positive and the other slope must be negative for each function.

with this in mind, the slopes of y = 2|x| are m = 2 and m = -2. the coefficient of 2 narrows the function by a factor of 2 (it is twice as narrow as the parent function). the same rules apply to y = 4|x| with the slopes of this function as m = -4 and m = 4 (it is 4 times narrower than the parent function).

with the fraction coefficients, the function is being widened. therefore, the slopes of y = 1/2 |x| are m = -1/2 and m = 1/2. the slopes of y = 1/5 |x| are m = -1/5 and m = 1/5.

6 0

2 years ago

An isosceles right triangle has<br>30 degree angles in its<br>interior.<br>B. False<br>A. True

Margarita [4]

False, an iso triangle has 2 equal sides like an icecream cone but are not limited to 30 degrees all the time.

7 0

3 years ago

Read 2 more answers

Divide 794.1 by 7.61. Round off your answer to two decimal places. A. 1,043.50 B. 95.83 C. 104.35 D. 786.49

Tcecarenko [31]

104.36 this is the answer

6 0

3 years ago

Graph the linear equation x=-1

kipiarov [429]

Answer:

See below

Step-by-step explanation:

It's just a vertical line drawn at x=-1. See the graph for a visual.

6 0

3 years ago

Find the area of the region enclosed by f(x) and the x axis for the given function over the specified u reevaluate f(x)=x^2+3x+4

lord [1]

Answer:

A = 68 unit^2

Step-by-step explanation:

Given:-

The piece-wise function f(x) is defined over an interval as follows:

f(x) = { x^2+3x+4 , x < 3

f(x) = { x^2+3x+4 , x≥3

Domain : [ -3 , 4 ]

Find:-

Find the area of the region enclosed by f(x) and the x axis

Solution:-

- The best way to tackle problems relating to piece-wise functions is to solve for each part individually and then combine the results.

- The first portion of function is valid over the interval [ -3 , 3 ]:

$f(x) = x^2+3x+4$

- The area "A1" bounded by f(x) is given as:

$A1 = \int\limits^a_b {f(x)} \, dx$

Where, The interval of the function { -3 , 3 ] = [ a , b ]:

$A1 = \int\limits^a_b {x^2+3x+4} \, dx\\\\A1 = \frac{x^3}{3} + \frac{3x^2}{2} + 4x |\limits_-_3^3 \\\\A1 = \frac{3^3}{3} + \frac{3*3^2}{2} + 4*3 - \frac{-3^3}{3} - \frac{3(-3)^2}{2} - 4(-3)\\\\A1 = 9 + 13.5 +12 + 9-13.5+12\\\\A1 =42 unit^2$

- Similarly for the other portion of piece-wise function covering the interval [3 , 4] :

$f(x) = 4x+10$

- The area "A2" bounded by f(x) is given as:

$A2 = \int\limits^a_b {f(x)} \, dx$

Where, The interval of the function { 3 , 4 ] = [ a , b ]:

$A2 = \int\limits^a_b {4x+10} \, dx\\\\A2 = 2x^2 + 10x |\limits_3^4 \\\\A2 = 2*(4)^2 + 10*4 - 2*(3)^2 - 10*3\\\\A2 = 32 + 40 - 18-30\\\\A2 =26 unit^2$

- The total area "A" bounded by the piece-wise function over the entire domain [ -3 , 4 ] is given:

A = A1 + A2

A = 42 + 26

A = 68 unit^2

8 0

2 years ago