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Tcecarenko [31]
3 years ago
11

Which inequality is true?

Mathematics
1 answer:
dsp733 years ago
8 0
The answer is b.
|2| = 2
|-4| = 4
4 is greater than 2.
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What is the vertex of the quadratic function f(x) = (x – 8)(x – 2)?<br><br> (<br> ,<br> )
irakobra [83]

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⅞2781x 3862

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i don't know but that is my answer ok kayat taposin Mona ang module mo

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Determine a possible 3rd degree polynomial function in factored form with its only zeros at (4,0) and (-1,0) and (-7,0)
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3 0
2 years ago
WILL GIVE BRAINLIEST!!! Given tan(theta) = 4/3 and pi &lt; theta &lt; (3pi)/2, find cos(2theta).
babymother [125]

Answer:  \cos 2 \theta = \dfrac{-7}{25}

Step-by-step explanation:

Given: \tan \theta = \dfrac{4}{3}  and  \pi < \theta< \dfrac{3\pi }{2}

To find: \cos 2 \theta

Now as we know

\cos 2x = \dfrac{1- \tan ^2 x}{1+ \tan ^2 x}

So we have

\cos 2 \theta = \dfrac{1-(\dfrac{4}{3} )^2}{1+(\dfrac{4}{3} )^2} \\\\\Rightarrow \cos 2 \theta = \dfrac{1- \dfrac{16}{9} }{1+ \dfrac{16}{9} } = \dfrac{\dfrac{9-16}{9} }{\dfrac{9+16}{9}} = \dfrac{-7}{25}

Therefore d. is the correct option

Hence , \cos 2 \theta = \dfrac{-7}{25}

3 0
3 years ago
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3 csc^2(2x) + 2 cosec 2x = 1-cot^2(2x)
asambeis [7]

I am assuming you want to solve for x:-

Now cosec^2 2x = 1 - cot^2 2x  so the equation becomes

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2 cosec^2 2x + 2 cosec 2x = 0

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so 2 cosec 2x = 0  or    cosec 2x = -1

cosec 2x = 0  or cosec 2x = -1

cosec 2x = 0  is indeterminate so we ignore the first one

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Therefore  x = 135 degrees  answer


3 0
3 years ago
5/9 , 4/15 ,dan 3/5
vichka [17]
4/15, 5/9 and 3/5.

Hope this helps! :)
5 0
3 years ago
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