6w^4+w³-3w²=w²(6w²+w-3)
☺☺☺☺
Answer:
146.41
Step-by-step explanation:
third order determinant = determinant of 3×3 matrix A
given ∣A∣=11
det (cofactor matrix of A) =set (transpare of cofactor amtrix of A) (transpare does not change the det)
=det(adjacent of A)
{det (cofactor matrix of A)} ^2 = {det (adjacent of A)}
^2
(Using for an n×n det (cofactor matrix of A)=det (A)^n−1
)
we get
det (cofactor matrix of A)^2 = {det(A) ^3−1
}^2
=(11)^2×2 = 11^4
=146.41
Answer:
I need Help on this one too.
Step-by-step explanation:
Answer: 6 hours
Step-by-step explanation:
$7.50per hour
$43.50 in tips
$88.50 total
88.50-43.50=45
45 divided by 7.50 equals 6
So your answer is 6 hours
Hope this helped:))
The first step in this equation is to Subtract 18 from both sides of the equation.
