8/15 x 5/6
•multiply across the numerator and denominator.
= 40/90
• then find a common factor that will go into both the numerator and denominator equally.
Common factor: 5
= 8/18
•there is another common factor, which is 2
Simplified:
=4/9
1. Set up the long addition.
2 4 7
+3 5 8
_______
2. Calculate 7+8, which is 15.
since 15 is two-digit, we carry the first digit 1 to the next column.
1
2 4 7
+ 3 5 8
________
5
3. Calculate 4+5, which is 9. Now add the carry digit of 1, which is 10. Since 10 is two-digit, we carry the first digit 1 to the next column.
1 1
2 4 7
+ 3 5 8
________
0 5
4. Calculate 2+3, which is 5. Now add the carry digit of 1, which is 6.
1 1
2 4 7
+3 5 8
______
6 0 5
5. Therefore, 247 + 358 = 605.
605
Answer:
Step-by-step explanation:
Given: There are 2 classes of 25 students.
13 play basketball
11 play baseball.
4 play neither of sports.
Lets assume basketball as "a" and baseball as "b".
We know, probablity dependent formula; P(a∪b)= P(a)+P(b)-p(a∩b)
As given total number of student is 25
Now, subtituting the values in the formula.
⇒P(a∪b)= 
taking LCD as 25 to solve.
⇒P(a∪b)= 
∴ P(a∪b)=
Hence, the probability that a student chosen randomly from the class plays both basketball and baseball is .
Answer:
Step-by-step explanation:
<em>Note. It should read 3/4 of an inch.</em>
- 3/4 in = 3 miles
- x in = 25 miles
<u>Cross multiply and solve for x:</u>
