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Mamont248 [21]
3 years ago
6

To raise funds for uniforms and travel expenses, the soccer team is holding a car wash in a part of town with a lot of car and t

ruck traffic. The team spent $90 on supplies like sponges and soap. They plan to charge $10 per car and $20 per truck. Their goal is to raise $460. How many cars do they have to wash if they washed the following numbers of trucks? 15 trucks
Mathematics
1 answer:
Harrizon [31]3 years ago
4 0

Answer:

The need to wash 16 cars.

Step-by-step explanation:

If they charge $20 per truck and washed 15, it would be $300. So you subtract $460 from $300. That gives you $160. Then, you divide $160 from $10. That gives you 16.

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(a)

\left[\begin{array}{ccccccccc} &1&2&3&4&5&6&7&8\\1&1&2&3&4&5&6&7&8\\2&2&4&6&8&10&12&14&16\\3&3&6&9&12&15&18&21&24\\4&4&8&12&16&20&24&28&32\\5&5&10&15&20&25&30&35&40\\6&6&12&18&24&30&36&42&48\\7&7&14&21&28&35&42&49&56\\8&8&16&24&32&40&48&56&64\end{array}\right]

(b)

(i)probability that the product of the two numbers is a prime number=7/64

(ii)probability that the product of the two numbers is not a perfect square=56/64

(iii)probability that the product of the two numbers is a multiple of 5 =15/64

(iv)probability that the product of the two numbers is Less than or equal to 21 =40/64

(v) probability that the product of the two numbers is divisible by 4 or 6 =42/64

Step-by-step explanation:

(a) 8-sided fair die implies each die can have outcomes 1,2,3,4,5.6,7,8 with equal chances.

To draw the possibility diagram of the product of the two numbers appearing on the die in each throw, we put the outcomes of both dies side by side and find the product of possible outcomes.

(b) probability= Number of outcome / Total number of outcomes

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based on sample space, the prime numbers are 2,2,3,3,5,5,7,7

(ii)probability that the product of the two numbers is not a perfect square=56/64=7/8

based on sample space, only  1,4,9,16,25,36,49,64 are perfect square

(iii)probability that the product of the two numbers is a multiple of 5 =15/64

(iv)probability that the product of the two numbers is Less than or equal to 21 =40/64=5/8

(v) probability that the product of the two numbers is divisible by 4 or 6 =42/64=21/32

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