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3 years ago

(Number 13) CAN SOMEONE PLEASE HELP ME!!

Mathematics

1 answer:

otez555 [7]3 years ago

7 0

A. 25 Keep in mind AB = BC!

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I just need to make sure this is correct for a test 6x² - 3x when x=5. my answer was 135

Allushta [10]

Answer:

135 is the correct answer

Step-by-step explanation:

6x^2-3x

substitution

x=5

6* (5*5) -3*5

6*25-3*5

150-15= 135

7 0

2 years ago

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Help me please. How to prove this ?

podryga [215]

Answer:

First, you want to divide the numerator and denominator by the cosine(x), and afterwards, it looks like this...

$\frac{tan~x+1}{tan~x-1}$

Include 45 as one of the parameters and correlate with tan.

$\frac{tan~x+tan~45}{tan~x-tan~45}$

Next, you want to multiply the numerator and denominator by the conjugate of the denominator, in this case, tan x + tan 45.

Lastly, simplify, and you have the answer as tan(45 + x)

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2 years ago

Instructions: Determine whether the following polygons are

sergiy2304 [10]

Answer:

None

Step-by-step explanation:

The given angles aren't equal which is needed for the polygon to be similar

7 0

3 years ago

The equation 4(x-2) = 100 is a true equation for a particular value of x. Explain why 2(x-2) = 50 is also true for the same valu

Mazyrski [523]

Answer:Figure it out your self.

Step-by-step explanation:

8 0

3 years ago

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Find the complex zeros of <img src="https://tex.z-dn.net/?f=%20f%28x%29%20%3D%20%7Bx%7D%5E%7B3%20%7D%20%20-%2013%20%7Bx%7D%5

timama [110]

$f(x) = 0 \\\\\implies x^3-13x^2+59x -87 =0\\\\\implies x^3 -3x^2 -10x^2 +30x +29x - 87=0\\\\\implies x^2(x-3) - 10x(x-3) + 29(x-3) =0\\\\\implies (x-3)(x^2 -10x +29) =0\\\\\implies x - 3 = 0 ~~ \text{or}~~x^2 -10x +29 = 0\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{-(-10) \pm \sqrt{(-10)^2 -4 \cdot 1 \cdot 29}}{2(1)}\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{10\pm \sqrt{-16}}{2}\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{10\pm 4i }{2}\\$

$\\\implies x =3~~ \text{ or} ~~ x =5 \pm 2i\\\\\text{Hence the complex roots are,}~ 5- 2i ~~ \text{and} ~~5 + 2i$

6 0

3 years ago