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SIZIF [17.4K]
3 years ago
13

If you answer all of these I will give brainliest if it will let me!!!!!

Mathematics
1 answer:
Tamiku [17]3 years ago
6 0

Answer:

1-8

Step-by-step explanation:

I was only able to finish one through eight The rest follow the same concept though

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HELPPP PLS SHOW WORK
expeople1 [14]

Answer:

61

Step-by-step explanation:

1. let the unknown be x

2. using theorem of Pythagoras that states the hypotenuse will be equal to the sum of the other two sides we can determine that 75=14+X

3. this implies that X=75-14

4. therefore X= 61

7 0
2 years ago
Easy math problems!!!!!
Alexandra [31]

Answer: 36

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Pls only do this if yk it because i’m giving correct answer brainliest! :))
Leno4ka [110]

Answer:

x=2+\frac{1}{2}\sqrt[]{21}

or

x=2-\frac{1}{2}\sqrt{{21}

Step-by-step explanation:

4x^2-16x-26=-21

Add 21 on both sides.

4x^2-16x-26+21=-21+21

4x^2-16x-5=0

a=4

b=-16

c=-5

x=\frac{-b\frac{+}{}\sqrt[]{b^2-4ac}  }{2a}

x=\frac{-(-16)\frac{+}{}\sqrt[]{(-16)^2-4(4)(-5)}  }{2(4)}

x=\frac{16\frac{+}{}\sqrt[]{256+80}  }{8}

x=\frac{16\frac{+}{}\sqrt[]{336}  }{8}

x=\frac{16\frac{+}{}\sqrt[]{2^2*2^2*21}  }{8}

x=\frac{16\frac{+}{}2*2\sqrt[]{21}  }{8}

x=\frac{16\frac{+}{}4\sqrt[]{21}  }{8}

---------------------------------------------------------------------------

x=\frac{16}{8}+\frac{4\sqrt[]{21}}{8}

x=2+\frac{1}{2}\sqrt[]{21}

---------------------------------------------------------------------------

x=\frac{16}{8}-\frac{4\sqrt[]{21}}{8}\\x=2-\frac{1}{2}\sqrt{{21}

6 0
3 years ago
Read 2 more answers
Let ​f(x)equals=33xminus−​1, ​h(x)equals=startfraction 7 over x plus 5 endfraction 7 x+5 . find ​(hcircle◦​f)(66​).
Ronch [10]
\bf \begin{cases}
f(x)=3x-1\\
h(x)=\cfrac{7}{x+5}\\\\
(h\circ f)(x)=h(~~f(x)~~)
\end{cases}
\\\\\\
f(66)=3(66)-1\implies \boxed{f(66)=197}
\\\\\\
\stackrel{h(~~f(x)~~)}{h(~~f(66)~~)}\implies \stackrel{h(~~f(66)~~)}{h\left(~~\boxed{197}~~ \right)}=\cfrac{7}{\boxed{197}+5}\implies h\left(~~\boxed{197}~~ \right)=\cfrac{7}{202}
7 0
3 years ago
What is the domain of the sine and cosine functions?
tatiyna

Remember that the domain is all possible x values of a function. In the case of sine and cosine functions, they go up and down (like waves), but go on forever. Therefore, the domain is all real numbers.

Correct Answer: B, All Real Numbers

Hope this helps!

6 0
3 years ago
Read 2 more answers
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