Given A = {1, 3, 5, 7, 9}, B = {2, 4, 6, 8, 10}, C = {1, 5, 6, 7, 9}
andrey2020 [161]
Answer:
ummmm thats not even a question
Step-by-step explanation:
There are infinite equivalent fraction can be obtained just multiple by any number to both numerator and denominator and you will find equivalent fraction !
as 42/16, 63/24 etc
n=3; We need a third degree polynomials with the following given zero's: 2 and 5i are zeros; f(-1)=156.
Since these are solutions
x = 2 ; x = 5i. Since imaginaries travel in pairs, the other answer is x= -5i.
We have (x-2)(x-5i)(x+5i) = 0
Now,
f(-1) = (-1-2)(-1-5i)(-1+5i) = 156.
f(-1) = (-3)(26) = -78.
But -78 x -2 = 156, so our polynomial becomes
Y= -2x (<em>x</em> - 2 ) x (<em>x </em>to the power of 2 + 25) = 0
Answer:
15
Step-by-step explanation:
a square root multiplied by itself equals the number inside the box, right?
(/~15~)2 = 15
