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ololo11 [35]
2 years ago
6

John and his friends are going out for pizza for lunch. They split one pizza and 3 drinks. The pizza cost $12.00. They spent a t

otal of $16.95. Find the cost of one large drink.
Mathematics
1 answer:
nika2105 [10]2 years ago
4 0
<span>John and his friends are going out for pizza for lunch. They split one pizza and 3 drinks. The pizza cost $12.00. They spent a total of $16.95. Find the cost of one large drink.
--pizza=P--      --drinks=D--   --john and his friends=J--
they split one pizza and 3 drinks...
(J=P+3D)
the pizza cost $12.00...
(P=$12)
since you know the value of P you plug it in...
(J=$12+3D)
they spent a total of $16.95...
J=$16.95
since you know the value of J you plug it in...
$16.95=$12+3D
and since you have only one unknown variable you can now solve by subtracting $12 on both sides...
$4.95=3D
then you divide 3 on both sides to keep the variable by itself...
$1.65=1D
and you end finding the cost of one drink
1D=$1.65 (D=$1.65)

</span>
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8 0
2 years ago
A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.
oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

H_0: \mu=2.4\\\\H_a:\mu> 2.4

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58

The degrees of freedom for this sample size are:

df=n-1=45-1=44

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>2.5801)=0.0066

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

7 0
3 years ago
Hello, can you explain this topic im in 6th grade ​
Andrew [12]

Hello there I hope you are having a great day :)

<u>The Topic Shifting digits:</u>

Shifting digits - Putting a digit in a different place. For a example Take the number 358 you would exchange the number from the hundreds that would equal 838 this meaning that you what to make a bigger number than a small one.

Examples:

1. 358 equal 838

2. 204 equal 402

3. 188 equal 881

You are just making them smaller to a greater number :)

Hopefully that helps you :)

 

<u></u>

5 0
2 years ago
Read 2 more answers
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