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Andru [333]
2 years ago
12

A 2-digit number with x units and 7 less units than tens.

Mathematics
1 answer:
Hatshy [7]2 years ago
7 0
Each two digit number has two numbers (duh!). Let's allow the tens digit to be x and the units digit to be y. Tens digit is 3 less than the units digit: x = y-3 Original number is 6 more than 4 times the sum of the digits: 10x+y-6 = 4x + 4y This gives us simultaneous equations!First let's clear the mess: 1. x= y-32. 6x-3y=6 Substitute 1 into 2: 6(y-3) -3y =66y - 18 - 3y = 6
 3y = 24y = 8 Our units digit is 8 Substitute y= 8 into 1. x = y - 3x = 5 Our tens digit is 5 Therefore, our number is 58
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[4 - (3c - 1)][6 - ( 3c - 1)]
Anestetic [448]
Hi there!

You would have to simplify the terms inside [ ] this thing, then multiply.

So let's simplify them first.

4 - (3c - 1) 
use distributive property.....
4 - 3c + 1
-3c + 5

6 - (3c - 1)
use distributive property again...
6 - 3c + 1
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so now, multiply (-3c + 5)(-3c + 7).
(-3c + 5)(-3c + 7)
9c² - 21c - 15c + 35
9c² - 36c + 35

So your final answer is...
9c² - 36c + 35

Hope this helped! :)
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