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zhenek [66]
3 years ago
14

Write a loop statement to count and display the number of positive integers in the array. That is, your loop should display the

message "Number of positive integers is 5". int myArray[] = { -1, 3, -9, 9, 33, -4, -5, 100, 4, -23};
Computers and Technology
1 answer:
dlinn [17]3 years ago
3 0

Answer:

int count =0;

    for(int i=0;i<10;i++)

    {

        if(myArray[i]>=0)

        {

            count++;

        }

    }

    cout<<"Number of positive integers is "<<count<<endl;

Explanation:

The above written loop is for counting positive integers in the myArray[].

For counting we have taken a count integer initialized with 0.On iterating over the array if the element is greater than or equal to 0 we consider it as positive and increasing the count.At the end printing the count.

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Answer:

#include <stdio.h>

int main()

{

//variable declaration

int low, high;

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for(int i=1; i<=12; i++)

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printf("%.1f ", rainfall[i]);

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//variable initialization

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for(int i=1; i<=12; i++)

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if(lowRain>rainfall[i])

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avg = total / 12;

 

//display the result

printf("\n\nThe total rain that fell was %.1f inches", total);

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}

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Answer::

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