<span>Evaluate when a = 8 and b = 4.
ab^2
a−b
ab² = (8)(4)² = 8*16= 128
a - b = 8 - 4 = 4 </span>
C.)
Since the ideal width is 7 cm and can vary by most 0.3 cm. This means the range is 6.7 cm to 7.3 cm Absolute value means that any negative number becomes positive. l 6.7 -7 l and l 7.3 - 7 l both equal 0.3 cm
l w - 7 l </= 0.3
The answer is 7.7 that is the answer
When reflecting over y = -x
The x and y values change places and the signs change.
(-2,5) becomes (-5,2)