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siniylev [52]
3 years ago
9

1.all real numbers that are less than -3 or greater than or equal to 5

Mathematics
2 answers:
Paha777 [63]3 years ago
7 0

1   is   a

2   is   b

3   is  b

hope   it   helped


SpyIntel [72]3 years ago
3 0
1) Is A- x < -3, or x> 5 (d=cant put the line under the second one) 
2) C- 25<*with line under* x >with line under*30 Because its between 25, so must be more, and 30, so has to be less than 30
3)?
4)?
                              
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3 our of 5 in two equivalent forms
sammy [17]
Hello!

3 out of 5 looks like this as a fraction:

3/5

We cannot divide this further as both the numerator and the denominator are odd numbers, so we must multiply to get an equivalent fraction:

3/5 = 6/10 = 60/100

3/5 is also equivalent to 0.2 as a decimal or 20% as a percentage.
7 0
3 years ago
PLEASE HELP I REALLY NEED HELP
Rainbow [258]

Answer:I believe that your asnwer is c.

Step-by-step explanation:

This is because -4 + 4 = 0 10 - 10 = 0 7-7 = 0

5 0
3 years ago
Verify that fand g are inverse functions (both questions please)
Grace [21]

Answer:

hope it helps you..,.....,..........

3 0
2 years ago
Assume that adults have IQ scores that are normally distributed with a mean of 96 and a standard deviation of 15.7. Find the pro
astraxan [27]

Answer:

4.05% probability that a randomly selected adult has an IQ greater than 123.4.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 96, \sigma = 15.7

Probability that a randomly selected adult has an IQ greater than 123.4.

This is 1 subtracted by the pvalue of Z when X = 123.4. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{123.4 - 96}{15.7}

Z = 1.745

Z = 1.745 has a pvalue of 0.9595

1 - 0.9595 = 0.0405

4.05% probability that a randomly selected adult has an IQ greater than 123.4.

7 0
3 years ago
88.83 is what percent of 21
Serjik [45]

88.83 / 21  =  4.23

4.23  is the same number as  423% .

8.23  is  <em>423%</em>  of  21.
6 0
3 years ago
Read 2 more answers
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