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Maslowich
2 years ago
14

It's a yes or no question​

Mathematics
1 answer:
wel2 years ago
3 0

Answer: No, figure A is not a scale copy of figure B.

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M<img src="https://tex.z-dn.net/?f=m%5E%7B2%7D%20-5m%2Bmn-5n" id="TexFormula1" title="m^{2} -5m+mn-5n" alt="m^{2} -5m+mn-5n" ali
Helen [10]
Equals (m-5)(m+n) by factoring
7 0
4 years ago
X^2+26x+c<br> find the value of c that makes each trinomial a perfect square
alekssr [168]

Answer:

c = 169

Step-by-step explanation:

We can use FOIL to determine this after factoring out the equation.

(x+13)(x+13)

F: (x*x)

O: (x*13)

I: (13*x)

L: (13*13)

x^2 + 26x + 169

3 0
4 years ago
Your soul is an appalling dump heap overflowing with the most disgraceful Assortment of deplorable rubbish imaginable, mangled u
ikadub [295]

Answer:

i think appalling dump heap overflowing  

Step-by-step explanation:

6 0
3 years ago
What is the equation of the line
konstantin123 [22]
Hello there!


The answer is B. \frac{2}{7}
-----------------------------------------------------------------------------------------------------

Explanation and Work:



We first must identify if the line goes through the origin or not. 

The origin is (0, 0) 

The line does go through the origin. This means that there is no y-intercept

The specific equation we would you use would be:

y = kx

K is the constant

We find this by finding the slope.

Slope is found by:

\frac{y2 - y1}{x2 - x1} 

y2 = 2

y1 = 0

x2 = 7

x1 = 0

Now, let's plug in these numbers.

\frac{2-0}{7-0} =  \frac{2}{7}

So, now let's plug he slope into our formula.

y = \frac{2}{7} x

So, our answer would be B.


I hope I helped!

Let me know if you need anything else!

~ Zoe


8 0
3 years ago
At a track meet, Tim ran at a constant speed of 300 meters per minute. After 8 minutes, he still had 600 meters left to run. The
gregori [183]
Okay so 300 meters per minute and he ran 8 minutes..

300x8=2400

He still had 600 left to go...

2400+600=3,000

He had to run three times longer than Eric...

3000/3=1000

Does that make sense?
8 0
3 years ago
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