Remember the quadratic formula determinant?
If b^2 -4ac < 0, a complex root exists.
So for this problem, m^2 - 4q is the determinant, and if less than 0, is complex.
So a=-m/2 and b=(1/2)SQRT(m^2 - 4q)
Answer:3.6364
Step-by-step explanation:
Because the 0 isn’t worth nothing & so the 4 stays the same
Answer:
B
Step-by-step explanation:
2.0 x 10^7
The area of the circle by definition is given by:

For f (r) = 154:

Clearing r we have:

For f (r) = 616:

Clearing r we have:
Answer:
a reasonable domain for f (r) is:
7 <r <14
It is b 4/3+2/3 is 6/3 and 6/3 divided by 1/3 is 2/3x