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olga_2 [115]
3 years ago
5

Reflect order pair (-2, 5) over y=-x

Mathematics
2 answers:
vesna_86 [32]3 years ago
8 0

When reflecting over y = -x

The x and y values change places and the signs change.

(-2,5) becomes (-5,2)

ivann1987 [24]3 years ago
5 0

Answer:

(-5,2)

Step-by-step explanation:

hope this helps

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2 years ago
Apply the distributive property and then combine like terms to write an equivalent expression
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x + 7(x + 1)

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3 0
3 years ago
Solve for m, what is k=mv​ squared/2​
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Step-by-step explanation:

4 0
2 years ago
Identify the center and the radius of a circle that has a diameter with endpoints at (−5, 9) and (3, 5)
marusya05 [52]

Check the picture below, so the circle looks more or less like that one.

well, the center of it is simply the Midpoint of those two points, and its radius is simply half-the-distance between them.

~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 3 -5}{2}~~~ ,~~~ \cfrac{ 5 + 9}{2} \right)\implies \left( \cfrac{-2}{2}~~,~~\cfrac{14}{2} \right)\implies \stackrel{center}{(-1~~,~~7)} \\\\[-0.35em] ~\dotfill

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[3 - (-5)]^2 + [5 - 9]^2}\implies d=\sqrt{(3+5)^2+(-4)^2} \\\\\\ d=\sqrt{8^2+16}\implies d=\sqrt{80}\implies d=4\sqrt{5}~\hfill \stackrel{\textit{half the diameter}}{\cfrac{4\sqrt{5}}{2}\implies \underset{radius}{2\sqrt{5}}}

8 0
2 years ago
What is the product of -3.4 and 2.5
qaws [65]
Your answer is -8.5

Can you mark as brainiest??
Please
8 0
3 years ago
Read 2 more answers
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