the area of a rectangle with the width x-5 and the length x-12 is 44 square feet. what are the dimensions

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

7 0

Answer: 23

Step-by-step explanation:

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Which of the algebraic expressions are not linear expressions? Select all that apply. a. 3x - 2 b. -9y c. -7x^2^ + 4x d. -1/2x^2

Sedaia [141]

Answer:

c, d and e

Step-by-step explanation:

A linear expression is an expression in which sum of exponents of variables is at most 1 in each of its terms.

Option a: $3x - 2$

Here, the exponent of the variable is 1.

So, it is a linear expression.

Option b: $-9y$

Here, the exponent of the variable is 1.

So, it is a linear expression.

Option c: $-7x^2 + 4x$

Here, the highest exponent of the variable is 2.

So, it is NOT a linear expression.

Option d: $-\frac{1}{2} x^2$

Here, the exponent of the variable is 2.

So, it is NOT a linear expression.

Option e: $8xy$

Here, sum of exponents of variables is 2.

So, it is NOT a linear expression.

Hence, c, d and e are NOT algebraic expressions.

6 0

3 years ago

Suppose scores on exams in statistics are normally distributed with an unknown population mean and a population standard deviati

Anna71 [15]

Answer:

( 67.18, 68.82)

Step-by-step explanation:

Let $\mu$ be the true (population) mean of statistics exam scores. We have a large random sample of n = 36 scores with a sample mean (sample mean score) of $\bar{x} = 68$ . We know that the population standard deviation is $\sigma = 3$ . A pivotal quantity is $(\bar{x}-\mu)/(3/\sqrt{36}) = (\bar{x}-\mu)/(3/6) = (68-\mu)/(1/2)$ which is approximately normally distributed and $P(-z_{0.05}\leq(68-\mu)/(1/2)\leq z_{0.05}) = 0.90$ where $-z_{0.05} =-1.6449$ , and so, $P(-1.6449\leq(68-\mu)/(1/2)\leq 1.6449) = 0.90$ . Therefore the 90% confidence interval is (68-(1/2)(1.6449), 68+(1/2)(1.6449)), i.e., ( 67.18, 68.82)