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postnew [5]
3 years ago
15

the area of a rectangle with the width x-5 and the length x-12 is 44 square feet. what are the dimensions

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
7 0

Answer: 23

Step-by-step explanation:

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Write the name of the period that has the digits 486
kogti [31]
1.       <span>The name of period that has 486 in the given number which is 751 486  is hundreds.
period is considered to a group of places of the digits, like the given number 486 is the group of hundred because the highest number it contains is 400.
=> 400 + 80 + 6
=> 4 hundreds + 8 tens + 6 ones
=> 486
while 751 is the period of hundred thousands.
=> 700 000 + 50 000 + 1 000
=> 751 000

</span>
8 0
3 years ago
HELP PLEASE 40 POINTS The graph shows the prices of different numbers of bushels of corn at a store in the current year. The tab
Vesna [10]

Answer:

see below

Step-by-step explanation:

Part A

Since the lines goes through the point (0,0) the graph is proportional. We can find the rate of change by take the price of corn and dividing by the number of bushels

24/3 = 8 dollars/ bushel

Part B

Previous Year Number of Bushels Price of Corn (dollars)

                                                  3 21

                                                 6 42

                                                  9 63

                                                 12 84

We can find the rate of change for the previous year by using the slope formula

m = (y2-y1)/(x2-x1)

m = (84-63)/(12-9)

    =21 / 3  

    = 7

The previous year was 7 dollars per bushel

The increase was 8-7 = 1 dollar per bushel

4 0
3 years ago
Read 2 more answers
I need help with this question is it A,B C or D
mixer [17]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Lim x-1 x2 - 1/ sin(x-2)
balu736 [363]

Answer:

           \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0

Explanation:

Assuming the correct expression is to find the following limit:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}

Use the property the limit of the quotient is the quotient of the limits:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}

Evaluate the numerator:

          \frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}

Evaluate the denominator:

  • Since         \lim_{x \to1}sin(x-2)\neq 0

                  \frac{0}{\lim_{x \to1}sin(x-2)}=0

4 0
3 years ago
Jonas solved an equation incorrectly, as shown below:
alexandr1967 [171]
So first he has to divide both sides by 8
wat
he multiplied the right side by 8 but divided left by 8
that is wrong


answer is 4th option
divid not divide 56 by 8
6 0
3 years ago
Read 2 more answers
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