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just olya [345]

3 years ago

13

The side of a box has length x feet, and another side has length (x-7) feet. What value of a would produce an area of 18 square

feet?

1 answer:

kozerog [31]3 years ago

5 0

Answer:

x=9

Step-by-step explanation:

(9-7) = 2

9 times 2 = 18 square feet

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Use the shell method to write and evaluate the definite integral that represents the volume of the solid generated by revolving

faust18 [17]

Answer:

$Volume = \frac{384}{7}\pi$

Step-by-step explanation:

Given (Missing Information):

$y = x^\frac{3}{2}$ ; $y = 8$ ; $x=0$

Required

Determine the volume

Using Shell Method:

$V = 2\pi \int\limits^a_b {p(y)h(y)} \, dy$

First solve for a and b.

$y = x^\frac{3}{2}$ and $y = 8$

Substitute 8 for y

$8 = x^\frac{3}{2}$

Take 2/3 root of both sides

$8^\frac{2}{3} = x^{\frac{3}{2}*\frac{2}{3}}$

$8^\frac{2}{3} = x$

$2^{3*\frac{2}{3}} = x$

$2^2 = x$

$4 =x$

$x = 4$

This implies that:

$a = 4$

For $x=0$

This implies that:

$b=0$

So, we have:

$V = 2\pi \int\limits^a_b {p(y)h(y)} \, dy$

$V = 2\pi \int\limits^4_0 {p(y)h(y)} \, dy$

The volume of the solid becomes:

$V = 2\pi \int\limits^4_0 {x(8 - x^{\frac{3}{2}}}) \, dx$

Open bracket

$V = 2\pi \int\limits^4_0 {8x - x.x^{\frac{3}{2}}} \, dx$

$V = 2\pi \int\limits^4_0 {8x - x^{\frac{2+3}{2}}} \, dx$

$V = 2\pi \int\limits^4_0 {8x - x^{\frac{5}{2}}} \, dx$

Integrate

$V = 2\pi * [{\frac{8x^2}{2} - \frac{x^{1+\frac{5}{2}}}{1+\frac{5}{2}}]\vert^4_0$

$V = 2\pi * [{4x^2 - \frac{x^{\frac{2+5}{2}}}{\frac{2+5}{2}}]\vert^4_0$

$V = 2\pi * [{4x^2 - \frac{x^{\frac{7}{2}}}{\frac{7}{2}}]\vert^4_0$

$V = 2\pi * [{4x^2 - \frac{2}{7}x^{\frac{7}{2}}]\vert^4_0$

Substitute 4 and 0 for x

$V = 2\pi * ([{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}] - [{4*0^2 - \frac{2}{7}*0^{\frac{7}{2}}])$

$V = 2\pi * ([{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}] - [0])$

$V = 2\pi * [{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}]$

$V = 2\pi * [{64 - \frac{2}{7}*2^2^{*\frac{7}{2}}]$

$V = 2\pi * [{64 - \frac{2}{7}*2^7]$

$V = 2\pi * [{64 - \frac{2}{7}*128]$

$V = 2\pi * [{64 - \frac{2*128}{7}]$

$V = 2\pi * [{64 - \frac{256}{7}]$

Take LCM

$V = 2\pi * [\frac{64*7-256}{7}]$

$V = 2\pi * [\frac{448-256}{7}]$

$V = 2\pi * [\frac{192}{7}]$

$V = [\frac{2\pi * 192}{7}]$

$V = \frac{\pi * 384}{7}$

$V = \frac{384}{7}\pi$

Hence, the required volume is:

$Volume = \frac{384}{7}\pi$

3 0

3 years ago

A right cylinder with radius 4 cm<br> and height 3 cm

SSSSS [86.1K]

Answer:

Step-by-step explanation:

$V=\pi r^2h=\pi *4^2*3\\=150.79645cm^3\\A=2\pi rh+2\pi r^2=2*\pi *4*3+2*\pi *4^2\\=175.93cm^2$

I put both volume and area

5 0

3 years ago

In 2010 Singapore welcome 11600000 overseas visitors.This value has been rounded off to the nearest 100000.What are the largest

spayn [35]

Answer:

The largest possible number of overseas visitors would be 11,640,000.

The smallest possible number of overseas visitors would be 11,550,000.

Step-by-step explanation:

The number 11,600,000 was rounded off to the nearest 100,000.

This means that either 0 or 1 was added to the figure with place value of 100,000.

It would be zero (0) in the case where the number after the 100,000th placed value number is lower than 5 and it would be one (1) in the case where the number after the 100,000th placed value is greater than or equal to 5.

Therefore, the largest possible number of overseas visitors would be 11,640,000.

The smallest possible number of overseas visitors would be 11,550,000.

7 0

3 years ago

HELP NEEDED !!!<br> find the size of unknown angles

Karolina [17]

<em><u>Explanation</u></em><em> </em><em>:</em>

The line DF is parallel to OB, therefore Angle x = Angle y.

( because, they for corresponding angle pair which are equal. )

And the angle made by an arc at center is always double the angle made by the same arc at its boundary, hence

x = 22° × 2

x = 44°

y = 44° ( cuz, x = y )

8 0

3 years ago

(-12) + (-5) = ?<br> Helpppp

Illusion [34]

Answer:

-17

Step-by-step explanation:

The answer is negative seventeen as you add the negatives together to get a higher negative

8 0

2 years ago