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deff fn [24]
3 years ago
10

A rectangular box is to have a square base and a volume of 50 ft3. The material for the base costs 42¢/ft2, the material for the

sides costs 10th¢/ft2, and the material for the top costs 30¢/ft2. Letting x denote the length of one side of the base, find a function in the variable x giving the cost (in dollars) of constructing the box.
Mathematics
1 answer:
Anni [7]3 years ago
8 0

Answer:

f(x)=72x^{2} +\frac{2000}{x}

Step-by-step explanation:

1) First of all, we are going to see what is the area of each element of the box.

The area of the base is x² (because x is the length of the side of the square base).

The area of the top is x² as well.

Now, the area of each side will be x·h where h is the height of the box. The box has 4 sides so the total area of the sides will be 4x·h

However, we can express h in terms of x because we have the total volume of the box:

V = (base area) · height = 50 ft³

50 = x²h

50/x² = h

Therefore, the area of the 4 sides will be: 4(x)(h) = 4x(\frac{50}{x^{2} } )=\frac{200}{x}

2) Now we are going to find the function giving the cost of constructing the box:

To find the function, we are going to use the prices we are given.

The price of the base, top and sides will be (for each of them): (price per ft²)(area in ft²)

Therefore the function to find the price (in cents) would be:

f(x)=42x^{2} +30x^{2} +(10)(\frac{200}{x} )\\f(x)=72x^{2} +\frac{2000}{x}

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How do I divide I don’t know how to it’s so confusing and how do you do the remainders
podryga [215]

Answer:

Step-by-step explanation:

set up the problem long division 487 divided by 32 Set up the division problem with the long division symbol or the long division bracket.

Put 487, the dividend, on the inside of the bracket. The dividend is the number you're dividing.

Put 32, the divisor, on the outside of the bracket. The divisor is the number you're dividing by.

step 1 divide dividend by divisor in long division 487 divided by 32 Divide the first number of the dividend, 4 by the divisor, 32.

4 divided by 32 is 0, with a remainder of 4. You can ignore the remainder for now.

step 2 subtraction in long division problem 487 divided by 32 Put the 0 on top of the division bracket.

This is the beginning of the quotient answer.

Next, multiply 0 by the divisor 32 and insert the result 0 below the first number of the dividend inside the bracket.

0 * 32 = 0

step 3 long division 487 divided by 32 Draw a line under the 0 and subtract 0 from 4.

4 - 0 = 4

step 4 long division 487 divided by 32 Bring down the next number of the dividend and insert it after the 4 so you have 48.

step 5 long division 487 divided by 32 Divide 48 by the divisor, 32. The answer is 1. You can ignore the remainder for now.

48 ÷ 32 = 1

Note that you could skip all of the previous steps with zeros and jump straight to this step. You just need to realize how many digits in the dividend you need to skip over to get your first non-zero value in the quotient answer. In this case you could divide 32 into 48 straight away.

step 6 long division 487 divided by 32 Put the 1 on top of the division bar, to the right of the 0. Next, multiply 1 by 32 and write the answer under 48.

1 * 32 = 32

step 7 long division 487 divided by 32 Draw a line and subtract 32 from 48.

48 - 32 = 16

step 8 long division 487 divided by 32 Bring down the next number from the dividend and insert it after the 16 so you have 167.

step 9 long division 487 divided by 32 Divide 167 by the 32. See a pattern emerging?

167 ÷ 32 is 5 with a remainder of 7

step 10 long division 487 divided by 32 Put the 5 on top of the division bar, to the right of the 1. Multiply 5 by 32 and write the answer under 167.

5 * 32 = 160

step 11 long division 487 divided by 32 Draw a line and subtract 160 from 167.

167 - 160 = 7

step 11 long division 487 divided by 32 Since 7 is less than 32 your long division is done. You have your answer: The quotient is 15 and the remainder is 7.

So, 487 ÷ 32 = 15 with a remainder of 7

For longer dividends, you would continue repeating the division and multiplication steps until you bring down every digit from the divdend and solve the problem.

3 0
3 years ago
What is the following product? 3√10(y^2√4 + √8y)
Elenna [48]

Answer:

6y^2√10 +12y √5

Step-by-step explanation:

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Distribute

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3y^2 √40+3y√80

We know that √ab = √a√b

3y^2 √4*√10+3y√16√5

3y^2 *2*√10+3y*4√5

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8 0
3 years ago
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Step-by-step explanation:

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4 years ago
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vivado [14]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
If XY × 8 = YYY, where Xand Y are digits of the numbers, then what is the value of Y?
kakasveta [241]
Given that
XY*8 = YYY ⇒⇒⇒ Where X and Y are digits
So, X is equal to one of the digits from 1 to 9
and Y is one of the digits from 1 to 9
This can be solved as following
YYY = 100Y + 10Y + Y = Y(100+10+1) = 111Y
XY*8 = 8 (10X + Y) = 80X + 8Y
∴ 80X + 8Y = 111Y
∴ 80 X = 111Y - 8 Y
∴ 80 X = 103 Y

∴ Y = 80X/103
substitute with X = 1 to 9
X = 1 ⇒⇒⇒ Y = 0.77 ⇒⇒ unacceptable

X = 2 ⇒⇒⇒ Y = 1.55 ⇒⇒ unacceptable
X = 3 ⇒⇒⇒ Y = 2.33 ⇒⇒ unacceptable
X = 4 ⇒⇒⇒ Y = 3.11 ⇒⇒ unacceptable
X = 5 ⇒⇒⇒ Y = 3.88 ⇒⇒ unacceptable
X = 6 ⇒⇒⇒ Y = 4.66 ⇒⇒ unacceptable
X = 7 ⇒⇒⇒ Y = 5.44 ⇒⇒ unacceptable
X = 8 ⇒⇒⇒ Y = 6.21 ⇒⇒ unacceptable

X = 9 ⇒⇒⇒ Y = 6.99 ⇒⇒ unacceptable

So, The is no value of  Y to achieve ⇒⇒ XY * 8 = YYY

================================================

I think the problem is as following:

Given that XY8 = YYY ⇒⇒⇒ Where X and Y are digits
So, X is equal to one of the digits from 1 to 9
and Y is one of the digits from 1 to 9
This can be solved as following
YYY = 100Y + 10Y + Y = Y(100+10+1) = 111Y
XY8 = 100X + 10Y + 8
∴ 100X + 10Y + 8 = 111Y
∴ 100x + 8 = 101Y
∴ Y = (100X + 8)/101
substitute with X = 1 to 9
X = 1 ⇒⇒⇒ Y = 1.07 ⇒⇒ unacceptable

X = 2 ⇒⇒⇒ Y = 2.06 ⇒⇒ unacceptable
X = 3 ⇒⇒⇒ Y = 3.05 ⇒⇒ unacceptable
X = 4 ⇒⇒⇒ Y = 4.04 ⇒⇒ unacceptable
X = 5 ⇒⇒⇒ Y = 5.03 ⇒⇒ unacceptable
X = 6 ⇒⇒⇒ Y = 6.02 ⇒⇒ unacceptable
X = 7 ⇒⇒⇒ Y = 7.01 ⇒⇒ unacceptable
X = 8 ⇒⇒⇒ Y = 8    ⇒⇒⇒ integer ⇒⇒ the correct answer

X = 9 ⇒⇒⇒ Y =8.99 ⇒⇒ unacceptable

So, The value of Y = 8
8 0
3 years ago
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