F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Let's say is "x", so, then "x" is the 100%, and we know that the 60% is 120, what the dickens is "x" anyway?
Thank you for posting you question here at brainly. I hope the answer will help you. The <span> practical domain and the practical range for this situation is below:
</span>D: [5, 7]
<span>R: [58, 81.2]
</span>
Feel free to ask more questions here at brainly. I'd be happy to answer.
Answer:
The answer shoudl be 6.2 miles
Step-by-step explanation:
