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3 years ago

In a hospital there are 56 TB patients. The patients are grouped with respect to their ages.

1 answer:

5 0

Table:

Class Boundaries Frequency

5-10 8

10-15 9

15-20 15

20-25 10

25-30 8

30-35 6
 ----------
total 56

Average =

[5+10]/2*8+[10+15]/2*9+[15+20]/2*15+[20+25]/2*10+[25+30]/2*8+[30+35]/2*6
---------------------------------------------------------------------------------------------------
 56

That is 1075 / 56 = 19.2

Answer: 19

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What is the difference between dash and hyphen

UNO [17]

Hyphens and Dashes. A hyphen joins two or more words together while a dash separates words into parenthetical statements. The two are sometimes confused because they look so similar, but their usage is different. Hyphens are not separated by spaces, while a dash has a space on either side.

8 0

3 years ago

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

3 years ago

Can you solve 2x + 17 = 29 by first dividing and then subtracting? Do you get the same answer if you subtract first and then div

nikdorinn [45]

Answer:

You cannot divide first because in equations you need to isolate the variable, which means subtracting first. The outcome will be different if you change the order.

8 0

3 years ago

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Help, please the question and thank you

Fynjy0 [20]

Answer:

Step-by-step explanation:

If A = (2, 3) then a dilation of scale factor 2 means that the x and y coordinates are multiplied by 2, so x = 2 x 2 = 4 and y = 3 x 2 = 6, so A' = (4, 6)

8 0

2 years ago

Two semicircles are attached to the sides of a rectangle as shown.

NeTakaya

Answer:

157 in²

Step-by-step explanation:

The area of the shape is the sum of three sections

1. Rectangle

A = 5*14 = 70 in²

2. Bigger semicircle

A = 1/2π(14/2)² = 76.96 ≈ 77 in² (rounded)

3. Smaller semicircle

A = 1/2π(5/2)² = 9.8174 ≈ 10 in² (rounded)

Total area:

70 + 77 + 10 = 157 in²

4 0

3 years ago

Read 2 more answers