Question

In a hospital there are 56 TB patients. The patients are grouped with respect to their ages.

Answer 1

Table:

Class Boundaries         Frequency

5-10                              8

10-15                            9

15-20                          15

20-25                          10

25-30                           8

30-35                           6
                                ----------
total                           56

Average =

[5+10]/2*8+[10+15]/2*9+[15+20]/2*15+[20+25]/2*10+[25+30]/2*8+[30+35]/2*6
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                                                      56

That is 1075 / 56 = 19.2

Answer: 19