Question

Multiply the polynomials. (2x2 + 6x + 6)(3x – 2)

Answer 1

Answer:

$6x^{3}+16x^{2} +6x-12$

Step-by-step explanation:

To calculate the result of that mutiplication you have to firs evaluate the first term of the second function multipying the whole first function, woudl be like this:

$(3x)(2x^{2}+6x+6)= 6x^{3}+18x^{2} +18x$

Now that you have this, you multiply the second term from the second function to obtain:

$(-2)(2x^{2}+6x+6)= -4x^{2}-12x-12$

Now you just have to add both results:

$6x^{3}+18x^{2} +18x$

+       $-4x^{2}-12x-12$

And the result of the sum would be:

$6x^{3}+16x^{2} +6x-12$