Answer:
14
Step-by-step explanation:
12+x=26
-12. -12
x=14
Answer: The height of the new player is 210 cm
Step-by-step explanation: The previous mean of the entire team has been calculated as 200.3
What this means is that, we have a summation of the observed data and a summation of the frequency of data.
The mean was calculated as
Sum FX/Sum F = 200.3
Where Sum FX is 2604 and Sum F is 13
However, our calculation should now read thus,
Sum FX/Sum F = 201 {where 201 is the new mean}
By cross multiplication we now have
Sum FX = Sum F x 201
Remember that a new member has joined the team so our Sum F is now 14 and we can now express it as thus
Sum FX = 14 x 201
Sum FX = 2814
If the summation of the observed data after adding a new team member is now 2814, then the addition to the previous observed data would be
2814 - 2604 = 210
So the height of the new member added to the team is 210 cm.
Answer:
The probability of using one or the other is 36%
Step-by-step explanation:
For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:
Probability of passing Professor Jones math class = 64% =0,64
P(J) = 0.64
Probabiliry of passing Professor Smith's physics class = 32% =0.32
P(S) = 0.32
Probability of passing both is = 30% = 0.30
P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram
We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:
P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%
If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.
Answer:
lokókà
haha
Step-by-step explanation:
góbôńìkásó