Question

The school cafeteria sells three different types of sandwiches: chicken, turkey,

Answer 1

Answer:

Number of chicken sandwiches = 150

Number of turkey sandwiches = 150

Number of roast beef sandwiches= 100

Step-by-step explanation:

We are told the school cafeteriat makes and sells 3 different types of sandwiches which are; chicken, turkey and roast beef.

Let chicken be x, turkey be y and roast beef be z.

We are told they make 400 sandwiches in total.

Thus;

x + y + z = 400

However, we are told that the cafeteria makes same number of chicken and turkey sandwiches.

Thus, x = y

Thus;

Total is now;

x + x + z = 400

2x + z = 400 - - - (eq 1)

Now,we are told that chicken, turkey and roast beef sandwiches are sold for $3, $3.5 and $4 respectively. Also that the total amount realized from sales is $1375.

Thus;

3x + 3.5y + 4z = 1375

Since x = y. Thus;

3x + 3.5x + 4z = 1375

6.5x + 4z = 1375 - - - (eq 2)

Let's make z the subject in eq 1.

Thus;

z = 400 - 2x - - - (eq 3)

Putting 400 - 2x for z in eq(2) gives us;

6.5x + 4(400 - 2x) = 1375

6.5x + 1600 - 8x = 1375

1600 - 1375 = 8x - 6.5x

225 = 1.5x

x = 225/1.5

x = 150

Putting 150 for x in eq 3 gives;

z = 400 - 2(150)

z = 400 - 300

z = 100

Since x = y. Then y = 150