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Arisa [49]
3 years ago
13

A triangle has side lengths of 10 inches, 24 inches, and 26 inches. is this a right triangle?

Mathematics
1 answer:
MrMuchimi3 years ago
7 0
To check it we can use Pythagorean theorem.
a^2+b^2=c^2, where c is the longest side.
Lets check it
Assume that a=10 and b= 24
10^2+24^2=100+576=676
Now lets compare with c^2=676
Its equal, so its right triangle.
You might be interested in
Determine two pairs of polar coordinates for the point (5, 5) with 0° ≤ θ < 360°.
inna [77]

Answer:

First part

The answer is (5 square root 2, 45°), (-5 square root 2, 225°) ⇒ answer (d)

Second part

The equation in standard form for the hyperbola is y²/81 - x²/19 = 1 ⇒ answer(b)

Step-by-step explanation:

First part:

* Lets study the Polar form and the Cartesian form

- The important difference between Cartesian coordinates and

  polar coordinates:

# In Cartesian coordinates there is exactly one set of coordinates

  for any given point.

# In polar coordinates there is an infinite number of coordinates

   for a given point. For instance, the following four points are all

   coordinates for the same point.

# In the polar the coordinates the origin is called the pole, and

  the x axis is called the polar axis.

# The angle measurement θ can be expressed in radians

   or degrees.

- To convert from Cartesian Coordinates (x , y) to

  Polar Coordinates (r , θ)

# r = ± √(x² + y²)

# θ = tan^-1 (y / x)

* Lets solve the problem

- The point in the Cartesian coordinates is (5 , 5)

∵ x = 5 and y = 5

∴ r = ± √(5² + 5²) = ± √50 = ± 5√2

∴ tanФ = (5/5) = 1

∵ tanФ is positive

∴ Angle Ф could be in the first or third quadrant

∵ Ф = tan^-1 (1) = 45°

∴ Ф in the first quadrant is 45°

∴ Ф in the third quadrant is 180 + 45 = 225°

* The answer is (5√2 , 45°) , (-5√2 , 225°)

Second part:

* Lets study the standard form of the hyperbola equation

- The standard form of the equation of a hyperbola with  

  center (0 , 0) and transverse axis parallel to the y-axis is

  y²/a² - x²/b² = 1, where

• the length of the transverse axis is 2a

• the coordinates of the vertices are (0 , ±a)

• the length of the conjugate axis is 2b

• the coordinates of the co-vertices are (±b , 0)

•      the coordinates of the foci are (0 , ± c),  

• the distance between the foci is 2c, where c² = a² + b²

* Lets solve our problem

∵ The vertices are (0 , 9) and (0 , -9)

∴ a = ± 9 ⇒ a² = 81

∵ The foci at (0 , 10) , (0 , -10)

∴ c = ± 10

∵ c² = a² + b²

∴ (10)² = (9)² + b² ⇒ 100 = 81 + b² ⇒ subtract 81 from both sides

∴ b² = 19

∵ The equation is  y²/a² - x²/b² = 1

∴  y²/81 - x²/19 = 1

* The equation in standard form for the hyperbola is y²/81 - x²/19 = 1

3 0
3 years ago
The figure shows the path of a track. It consists of a semicircular arc BCD and three sides of a rectangle in which AB = 20 cm,
fredd [130]

\large \mathcal{Answer}

A. Area of given figure = 280 + 77 = 357 cm²

B. length of semicircle = 22 cm

7 0
3 years ago
Bob,Cal,and Pete each made a stack of baseball cards.Bob's stack was 0.2 meter high.Cal's stack was 0.24 meter high.Pete's stack
AlekseyPX

Answer:

0.24 > 0.18

Step-by-step explanation:

Given that,

Bob's stack = 0.2m

Cal's stack = 0.24m

Pete's stack = 0.18m

To find?

A number sentence.

<em>A simple sentence is a string/collection of words that contain a subject and a verb whereas a number sentence is a sentence that consist of </em><em>mathematical operation</em><em> like +, -, /, * together with an equality such as =, <, >, and like a sentence it also tell a fact.</em>

<em> </em>So, the number sentence that compares cal's stack of cards to Pete's stack is

<h2>0.24 > 0.18</h2>

<em />

<em />

<em>  </em>

6 0
3 years ago
Read 2 more answers
Can any help me with this question
Y_Kistochka [10]
Ok...there are 6 days in the week that end in a y: Monday, Wednesday, Thursday, Friday, Saturday, Sunday.
Saturday is one out of the 6, so it's 1/6....If they want it as a percent, then divide 1 by 6, and multiply it by 100.

Hope I helped!
4 0
3 years ago
I need help with this homework can anyone help me. I need work too, help is appreciated:)
quester [9]
Let x = # of tickets sold in advance 
Let y = # of tickets sold the day of 


Cost of the tickets & total sales: 6x & 10y = 6828

You also know y = x + 206

Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828

Now solve for x to get x = 298

To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.

So, 298 tickets were sold in advance and 504 tickets were sold the day of
3 0
3 years ago
Read 2 more answers
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