Using it's concept, it is found that the graph has no horizontal asymptote.
<h3>What are the horizontal asymptotes of a function f(x)?</h3>
The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.
In this problem, we have that:
- The function is undefined for x < 0, hence
is undefined.
- For x > 0, the funciton goes to infinity, hence
.
Thus, the graph has no horizontal asymptote.
More can be learned about horizontal asymptotes at brainly.com/question/16948935
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Answer:
x = ±4
Step-by-step explanation:
Step 1: Write out quadratic
2x² - 5 = 27
Step 2: Add 5 to both sides
2x² = 32
Step 3: Divide both sides by 2
x² = 16
Step 4: Take the square root of both sides
x = ±4
∴ x can equal -4 or 4
We have to present the number 41 as the sum of two squares of consecutive positive integers.
1² = 1
2² = 4
3² = 9
4² = 16
5² = 25
16 + 25 = 41
<h3>Answer: 4 and 5</h3>
Other method:
n, n + 1 - two consecutive positive integers
The equation:
n² + (n + 1)² = 41 <em>use (a + b)² = a² + 2ab + b²</em>
n² + n² + 2(n)(1) + 1² = 41
2n² + 2n + 1 = 41 <em>subtract 41 from both sides</em>
2n² + 2n - 40 = 0 <em>divide both sides by 2</em>
n² + n - 20 = 0
n² + 5n - 4n - 20= 0
n(n + 5) - 4(n + 5) = 0
(n + 5)(n - 4) = 0 ↔ n + 5 = 0 ∨ n - 4 =0
n = -5 < 0 ∨ n = 4 >0
n = 4
n + 1 = 4 + 1 = 5
<h3>Answer: 4 and 5.</h3>
Answer:92.6013
Step-by-step explanation:
X=2W+1-1/Y
YOU SUBTRACT 2/Y TO START TO GET X ALONE.
WHICH WOULD MAKE IT 2X=4W+2-2/Y.
THEN YOU MUST DIVIDE BOTH SIDE BY TO FINISH GETTING X ALONE WHICH WOULD GIVE YOU YOUR ANSWER
