Answer:

Step-by-step explanation:
The result is given by means of some algebraic handling:

- Multiplication of rationals.
- Dividing each term by 2.
- Dividing each term by 2.
- Dividing each term by 3.
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Explanation:</h2><h2>
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The diagram is missing but I'll assume that the arc BDC is:

And another arc, let's call it FGH. measures:

If those arc are equal, then this equation is true:

Substituting k into the first equation:

Cube has 6 faces/planes :)
You have to use sin, cos, tan and find the length of the last side and other angles. Then you have to put an imaginary line down the middle and use the sin, cos, tan to find the height and then do 1/2 base times height.
Answer:
yous math symblom
Step-by-step explanation:
its a good website for that