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Dmitriy789 [7]
3 years ago
8

4p + 5c = p. Solve for c

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
4 0

Answer:

4p + 5c = p

4p - 4p + 5c = p-4p

5c = -3p

5c/5 = -3p/5

c = -3p/5

hope that will help you

madam [21]3 years ago
3 0
Minus 4p on both sides
you end up with 5c = -3p
divide by 5 on both sides
c = -3/5p
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3 (x+2)+9<6(x-3) solve the inequality and write the solution using interval notation​
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(11, ∞).

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3 (x+2)+9<6(x-3)

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The initial quantity at T= 0 is 1000z the quantity grows by a factor 3%. What is the quantity at T=5?
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A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 335335 babies were​ born
strojnjashka [21]

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Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 335, \pi = \frac{268}{335} = 0.8

99% confidence level

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The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563

For the percentage:

Multiplying the proportions by 100.

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

7 0
3 years ago
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