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RoseWind [281]
3 years ago
14

Point E is between points D and F. If DE = x − 2, EF = 6x + 4, and DF = 8x − 2, find x

Mathematics
1 answer:
Arlecino [84]3 years ago
3 0
DE + EF = DF

x - 2 + 6x + 4 = 8x - 2
7x + 2 = 8x - 2
2 + 2 = 8x - 7x
4 = x <===
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Fudgin [204]

Answer:

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\text{Distance Formula=}\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\text{Radius=}\sqrt{(2-(-4))^2+(2-(-6))^2} \\=\sqrt{(2+4))^2+(2+6)^2}\\=\sqrt{6^2+8^2}\\=\sqrt{100}\\Radius=10

Step 2: Determine the equation

The general form of the equation of a circle passing through point (h,k) with a radius of r is given as: (x-h)^2+(y-k)^2=r^2

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Therefore, the equation of the circle is:

(x-(-4))^2+(y-(-6))^2=10^2\\\\(x+4)^2+(y+6)^2=100

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3 years ago
Mrs. Walker is instructing a team of students on designing the sailboat shown. Beth is working on the smaller sail, which is a r
Pachacha [2.7K]

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Read 2 more answers
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K.E=0.5mv^2
GPE=mgh
The child has both K.E and GPE
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g is taken as 9.81
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4. (03.06 MC)
bazaltina [42]

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If a car goes from 0 to 60 mph in 8.0 seconds, its acceleration would be 60/8 which is equal to 7.5mph/sec
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