In the triangle ABC if angle A is 20 degrees, angle B is 35 degrees and the side between (side C) them is 100, what is the appro
1 answer:
Answer:length of side a is 42
Step-by-step explanation:
The given triangle ABC is shown in the attached photo. The length of side BC is a. The length of side AC is b and the length of side AB is c = 100
The sum of the angles in a triangle is 180 degrees. Therefore.
Angle A + angle B + angle C = 180. Therefore,
20 + 35 + angle C = 180
55 + angle C = 180
Angle C = 180 - 55 = 125 degrees. To determine the length if a, we would apply the sine rule which is expressed as
a/SinA = b/SinB = c/SinC
Therefore,
a/Sin20 = 100/Sin125
aSin125 = 100sin20
a × 0.8192 = 0.342 × 100
0.8192a = 34.2
a = 34.2/0.8192
a = 41.75
Approximately 42
You might be interested in
Answer:
7 out of 8
Step-by-step explanation:
Answer:
53/5
Step-by-step explanation:
Multiply both sides by 5: 5x - 3 = 50
Add 3 to both sides: 5x = 53
Divide both sides by 5: x = 53/5
Answer:
A) SUBTRACT 3x by both sides of the bottom equation.