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KiRa [710]
4 years ago
10

What is one of the main differences between a 401(k) and a Roth 401(k)

Mathematics
2 answers:
Leviafan [203]4 years ago
8 0

Answer:

Contributions are taxed differently Apex

Step-by-step explanation:

Dennis_Churaev [7]4 years ago
3 0
The difference between a 401(k) and a Roth 401(k) is that 401(k) is the income taxes on distribution whereas the Roth 401(k) is the income taxes on contribution.
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he would have 11 kites in total, hope this helps!

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3 years ago
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avanturin [10]
Here you go the answer is in the picture

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3 years ago
Respond to each of the following questions. Be sure to include and thoroughly describe each transformation.
sergeinik [125]

Answer:

31. 1) Vertical shift up 4 units.

     2) Horizontal shift right 1 unit.

     3) Vertically stretched by a factor of 3.

32. g(x)=-(x+3)^2+7

Step-by-step explanation:

Some transformations for a function f(x) are shown below:

- If f(x)+k, the function is shifted up "k" units.

- If f(x)-k, the function is shifted down "k" units.

- If f(x+k), the function is shifted left "k" units.

- If f(x-k), the function is shifted right "k" units.

- If -f(x), the function is reflected over the x-axis.

- If bf(x) and b>1, the function is stretched vertically by a factor of "b".

31. Given the function f(x)=x^{2} and the function g(x) = 3(x - 1)^2 + 4, we can notice that the transformations from the graph of f(x) to the graph of g(x) are:

1)  f(x)+k

2)  f(x-k)

3)  bf(x), being b>1

Therefore, we can conclude that the transformations necessary to transform the graph of f(x) to the graph g(x) are:

1) Vertical shift up 4 units.

2) Horizontal shift right 1 unit.

3) Vertical stretch by a factor of 3.

32. Knowing the parent function:

 f(x)=x^{2}

And given the transformations:

1) Reflection over the x-axis.

2) Horizontal shift left 3 units.

3) Vertical shift up 7 units.

We can define that the function g(x) is:

g(x)=-(x+3)^2+7

7 0
3 years ago
Hello can someone please help?
Ray Of Light [21]
The answer is D
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7 0
3 years ago
The​ function, ​p(d)equals=1plus+startfraction d over 33 endfraction d 33​, gives the​ pressure, in atmospheres​ (atm), at a dep
Gelneren [198K]

Answer:

The pressure at 50 feet is 2.51515 atm

Step-by-step explanation:

we are given equation as

p(d)=1+\frac{d}{33}

where

p(d) gives the​ pressure, in atmospheres​ (atm)

a depth d in the sea​ (d is in​ feet)

We are given

d=50 feet

So, we can plug d=50 and find p

p(50)=1+\frac{50}{33}

p(50)=2.51515atm

So,

The pressure at 50 feet is 2.51515 atm

7 0
3 years ago
Read 2 more answers
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