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Allisa [31]
3 years ago
7

A square can be. Rhombus, and figure X is a rhombus, so figure X must be a square. True or false

Mathematics
2 answers:
vekshin13 years ago
4 0
I believe this is false because not necessarily does a rhombus have to be a square
kvasek [131]3 years ago
3 0
I have to go with True because a Rhombus is a Square. 
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What values of x satisfy the equation 2x^2 -3x +4 =0
BaLLatris [955]

Answer:

(3 ± √23 * i) /4

Step-by-step explanation:

To solve this, we can apply the Quadratic Equation.

In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)

Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4

Plugging these values into our equation, we get

x = (-b ± √(b²-4ac))/(2a)

x = (-(-3) ± √(3²-4(2)(4)))/(2(2))

= (3 ± √(9-32))/4

= (3 ± √(-23))/4

= (3 ± √23 * i) /4

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3 years ago
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Answer:

Use the method for solving Bernoulli equations to solve the following differential equation.

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Step-by-step explanation:

Use the method for solving Bernoulli equations to solve the following differential equation.

StartFraction dy Over dx EndFraction plus StartFraction y Over x minus 9 EndFraction equals 5 (x minus 9 )y Superscript one half

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What’s the distance between (-9,-3) and y=x-6
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hopefully this will help :)

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Question 2
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1 is answer

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