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3 years ago

A square can be. Rhombus, and figure X is a rhombus, so figure X must be a square. True or false

Mathematics

2 answers:

vekshin13 years ago

4 0

I believe this is false because not necessarily does a rhombus have to be a square

kvasek [131]3 years ago

3 0

I have to go with True because a Rhombus is a Square.

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Probably of Carl solving the 10 problems if there's 20 to study and he knows 15 and ten of the 20 are on the test.

Vladimir79 [104]

Answer:

1/3

Step-by-step explanation:

Probability of solving ten problems by Carl

Given

Total number of problems = 20

Number of problems studied by Carl = 15

Number of problems out of the 20 set of problem coming in test is 10

Case I - All ten problems come from the set of known 15 question

10/15 * 10/20 = 1/3

8 0

3 years ago

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0

4 years ago

The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

Part B

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$

Part C

$\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971$

6 0

2 years ago

Caleb started saving money in a cookie jar. He started with $25 .He adds $10 to the cookie jar each week. Write an equation wher

Kryger [21]

It would be, t= 10w + 25 And to make a graph but in values for w; w: 1 / 2 / 3 / 4 t: 35/ 45 / 55 / 65 And then you plot the points on the graph.

8 0

3 years ago

2b plus 4a minus a minus 2 plus 12b

jarptica [38.1K]

The value of the expression 2b plus 4a minus a minus 2 plus 12b is 3a + 14b - 2.

Expression:

An expression is defined as the a combination of operators, constants and variables. And it may consist of one or more operands, and zero or more operators to produce a value.

Given,

Here we have the statement "2b plus 4a minus a minus 2 plus 12b".

Now, we have to find the simplified form of this statement.

In order to find the simplified form,

First we have to convert the statement into expression form, then we get

2b plus 4a minus a minus 2 plus 12b = 2b + 4a - a - 2 + 12b

Now, we have to combine the like terms, then we get,

=> (2b + 12b) + (4a - a) - 2

Perform the appropriate arithmetic operations, then we get the simplified form of the expression as,

=> 14b + 3a - 2

Now, we have to arrange them in order then we get,

=> 3a + 14b - 2

To know more about Expression here.

brainly.com/question/14083225

#SPJ1

8 0

1 year ago