A square can be. Rhombus, and figure X is a rhombus, so figure X must be a square. True or false
2 answers:
You might be interested in
Answer:
If then
and
a | b | a + b (answer)
0 | 0 | 0
0 | 1 | 1
0 | 2 | 2
1 | 0 | 1
2 | 0 | 2
1 | 1 | 2
2 | 1 | 3
Step-by-step explanation:
Considering the following conditions for the real numbers:
Following the rules of these in-equations, it is possible to deduce:
Then, if the proposed statement is:
The conditions above shall comply the requirements established, but first, analyzing the statement:
If and
then
,
and
.
If and b a non negative real number, then
, but because to
, then
. Due to the commutative property of sums, the same behavior will be presented if
and a a non negative real number.
According to that, if , then
and
.
The system of equations have 2 solutions
<h3>How to determine the number of solutions?</h3>The system of equations is given as:
-1/3x² = 5/6 + 1/3y²
5y² = 25/2 - 5x²
Next, we plot the graph of the system of equations.
From the attached graph, the equations intersect at two points
Hence, the system of equations have 2 solutions
Read more about system of equations at:
#SPJ1
