To find the area of a rectangle, multiple the width by the length.
(And simply the fractions for a simpler equation)
For piece A:
The length 1 and 3/5 can be turned into an improper fraction by multiplying 1 by the denominator (5) and adding it to the numerator (3). 1 and 3/5 = 8/5
(3/4) • (8/5) = area
Multiple the numerators with each other and the denominators with each other (3 times 8 = 24) (4 times 5 = 20)
The area of piece A is 24/20
If you do the same for piece B:
(2/5) • (21/8) = area
The answer is 42/40
Yes. Changing the the word problem into a function, you get 30x=y.
30 = Fixed Length
x = width
y = area
No matter what width (x) you choose, the area (y) is going to be a multiple of 30 (the fixed length) because with two numbers being multiplied, if there is a fixed number that will always be the multiple and not the multiplier. For example, 10 multiplied by every number 1-10 is going to be a multiple of 10.
10x1=10, 10x2=20, 10x3=30, etc
So if Tom chooses any of these widths (x) 5, 10, or 15, y (the area) will be a multiple of 30.
30(5)=150
30(10)=300
30(15)=450
So as we double 5 to get 10, our outcome is doubled 150 to 300 and so forth. Hope this helps.
In the 
direction we consider the 
subintervals [0, 1] and [1, 2] (each with length 1), while in the 
direction we consider the 
subintervals [0, 2] and [2, 4] (with length 2). Then the lower right corners of the cells in the partition of 
are (1, 0), (2, 0), (1, 2), (2, 2).
Let 
. The volume of the solid is approximately
###
More generally, the lower-right-corner Riemann sum over 
and 
subintervals would be
Then taking the limits as 
and 
leaves us with an exact volume of 
.
Answer:
48?
Step-by-step explanation:
24+24=48
I'm not sure if this is right
