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olya-2409 [2.1K]
3 years ago
14

Write repeating decimal as a fraction 0.2045454545

Mathematics
1 answer:
Mkey [24]3 years ago
5 0
First, we need to move the decimal point directly in front of the repeating part. To do this, we need to move it two places to the right, which we can do by multiplying by 100.

100 × 0.2045454545 = 20.45454545

Now we need to subtract our original number.

\ 20.454545...\\\underline{-0.204545...}\\20.25

Now we put that over 99 (that's one less than our 100 from earlier)

\frac{20.25}{99}

Our fraction is shaping up, but we shouldn't have a decimal in there. Let's multiply the top and bottom by 100 to get rid of it.

\frac{2025}{9900}

We're going to have to do some simplifying. (the top and bottom are both clearly divisible by 5 and then some)

\frac{2025}{9900}=\frac{405}{1980}=\frac{81}{396}=\frac{27}{132}=\boxed{\frac{9}{44}} <em> done!</em>
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Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

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Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

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Row Operation 2: add -2 times the 1st row to the 3rd row

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The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

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If two figures are similar, then the ratio of the corresponding sides is proportional.

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