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gayaneshka [121]
3 years ago
7

A coat has been marked down 20% to $26.40 what was it's original value?

Mathematics
1 answer:
Gemiola [76]3 years ago
6 0
20% is equal to 0.2
0.2 times 26.40 is equal to 5.28
26.40 minus 5.28 is equal to 21.12
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2a + 2b = c for b<br> Solve for b
Leokris [45]

2a + 2b = c

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2b = -2a + c

Divide both sides by 2

b = -a + (c/2)

7 0
3 years ago
(PLEASE HELP!!) Use the following diagram to answer the questions.
monitta

Answer:

x:

5x - 29 = 3x+ 19

2x = 48

x = 24°

Angle 1:

180 - (3x+7) = 180 - 79 = 101°

Angle 2:

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Angle 3:

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Angle 4:

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Angle 5:

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Angle 6:

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Angle 7:

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Angle 8:

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4 years ago
1726 rounded to the nearest 100
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Answer:

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6 0
3 years ago
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A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate
Lyrx [107]

Answer:

Therefore the rate change of height is  \frac{1}{\pi} m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

\frac{dV}{dt}=4 \ m^3/s

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is V=\pi r^2 h

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\therefore V= 4\pi h

Differentiating with respect to t.

\frac{dV}{dt}=4\pi \frac{dh}{dt}

Putting the value \frac{dV}{dt}

\Rightarrow 4\pi \frac{dh}{dt}=4

\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}

\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}

The rate change of height does not depend on the height.

Therefore the rate change of height is  \frac{1}{\pi} m/s.

3 0
3 years ago
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Debora [2.8K]

Answer:

D

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4 0
2 years ago
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