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3 years ago

NEED HELP FOR THIS QUICK (WILL SEND MONEY IF DONE)

Mathematics

1 answer:

lilavasa [31]3 years ago

6 0

Answer:

_Area top_= √1/4(a+b+c)(b+c−a)(c+a−b)(a+b−c) + _Area bottom_ √1/4(a+b+c)(b+c−a)(c+a−b)(a+b−c)+ Area lateral =h(a+b+c)

1) Surface Area: 76,017.691

√V=1/4h(a+b+c)(b+c−a)(c+a−b)(a+b−c)

2) Volume: 631,332.519

Volume - given empty space

3) 631,332.519 - 335,954.96= 295,377.559

Percentage of 335,954.96 in 631,332.519=

Bonus Question) 53.21%

Step-by-step explanation:

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3 years ago

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Nutka1998 [239]

Answer:

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3 years ago

Form a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3

polet [3.4K]

The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is $x^3-3x^2-x+3=0$

Step-by-step explanation:

We need to find a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3.

If -1, 1 and 3 are real zeros, it can be written as:

x= -1, x= 1, and x = 3

or x+1=0, x-1=0 and x-3=0

Finding polynomial by multiply these factors:

$(x+1)(x-1)(x-3)=0\\(x+1)(x(x-3)-1(x-3))=0\\(x+1)(x^2-3x-x+3)=0\\(x+1)(x^2-4x+3)=0\\x(x^2-4x+3)+1(x^2-4x+3)=0\\x^3-4x^2+3x+x^2-4x+3=0\\Combining\,\,like\,\,terms:\\x^3-4x^2+x^2+3x-4x+3=0\\x^3-3x^2-x+3=0$

So, The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is $x^3-3x^2-x+3=0$

Keywords: Real zeros of Polynomials

Learn more about Real zeros of Polynomials at:

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3 years ago

What is the value of x? <br> X=

brilliants [131]

Answer:

x=7

step-by-step explanation:

$\frac{5}{40} = \frac{3}{2x + 10}$

5(2x+10) =3×40

10x + 50 = 120

10x =120-50= 70

x = 70/10= 7

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3 years ago

Find the height of the triangle if the area is 36 m 2

n200080 [17]

Answer:

Area=1/2bh

Given area of 36m^2

1/2(x)(x-1)=36

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(x)(x-1)=72

X^2-x=72

X^2-x-72=0 then factor

(x-9)(x+8)=0

X=9,-8 however since area must be positive, take the absolute value of 8

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3 years ago